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We are given a list nums of integers representing a list compressed with run-length encoding.
Consider each adjacent pair of elements [a, b] = [nums[2*i], nums[2*i+1]] (with i >= 0). For each such pair, there are a elements with value b in the decompressed list.
Return the decompressed list.
Example 1:
Input: nums = [1,2,3,4]
Output: [2,4,4,4]
Constraints:
2 <= nums.length <= 100
nums.length % 2 == 0
1 <= nums[i] <= 100
给你一个以行程长度编码压缩的整数列表 nums 。
考虑每相邻两个元素 [a, b] = [nums[2*i], nums[2*i+1]] (其中 i >= 0 ),每一对都表示解压后有 a 个值为 b 的元素。
请你返回解压后的列表。
示例:
输入:nums = [1,2,3,4]
输出:[2,4,4,4]
提示:
2 <= nums.length <= 100
nums.length % 2 == 0
1 <= nums[i] <= 100
1 class Solution { 2 func decompressRLElist(_ nums: [Int]) -> [Int] { 3 var res:[Int] = [Int]() 4 for i in stride(from:0,to:nums.count,by:2) 5 { 6 for j in 0..<nums[i] 7 { 8 res.append(nums[i + 1]) 9 } 10 } 11 return res 12 } 13 }