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  • 【leetcode】Clone Graph

    Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


    OJ's undirected graph serialization:

    Nodes are labeled uniquely.

    We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

    As an example, consider the serialized graph {0,1,2#1,2#2,2}.

    The graph has a total of three nodes, and therefore contains three parts as separated by #.

    1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
    2. Second node is labeled as 1. Connect node 1 to node 2.
    3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

    Visually, the graph looks like the following:

           1
          / 
         /   
        0 --- 2
             / 
             \_/

    题解:利用DFS递归的方法克隆图,用hashmap保存原图中的节点和新图中的节点的对应关系。而且利用这个hashmap可以在O(1)的时间内判断一个节点是否被克隆过,并且知道克隆它得到的新节点。

    实现一个克隆节点的方法,在这个方法中:

    1. 判断这个节点是否被clone过了,如果是,返回它对应的clone节点;
    2. 如果没有被clone过,那么新建节点为该节点的clone节点,并且递归的clone它的邻居节点,放入该节点的neighbors列表里面;

    代码如下:

     1 /**
     2  * Definition for undirected graph.
     3  * class UndirectedGraphNode {
     4  *     int label;
     5  *     List<UndirectedGraphNode> neighbors;
     6  *     UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
     7  * };
     8  */
     9 public class Solution {
    10     private HashMap<UndirectedGraphNode,UndirectedGraphNode> mapClone = new HashMap<UndirectedGraphNode,UndirectedGraphNode>();
    11     
    12     private UndirectedGraphNode cloneNode(UndirectedGraphNode node){
    13         if(node == null)
    14             return null;
    15         //if this node already has a clone
    16         if(mapClone.containsKey(node))
    17             return mapClone.get(node);
    18         
    19         //if this node hasn't been cloned, we construct a new node copy
    20         UndirectedGraphNode copy = new UndirectedGraphNode(node.label);
    21         mapClone.put(node, copy);
    22         
    23         //clone all the neighbers of node
    24         for(UndirectedGraphNode n:node.neighbors){
    25             copy.neighbors.add(cloneNode(n));
    26         }
    27         return copy;
    28     }
    29     public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
    30         return cloneNode(node);
    31     }
    32 }
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  • 原文地址:https://www.cnblogs.com/sunshineatnoon/p/3854707.html
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