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1 function result = matrix_change(X,m1,n1)
2 %需要变换的矩阵,分割成m1*n1区域求均值
3 [m,n] = size(X);
4 solution=reshape(sum(reshape(X,m1,[])),[],n);
5 solution_z=reshape(sum(reshape(solution',n1,[])),[],m/m1);
6 result=solution_z'/(m1*n1);
调用:
View Code
clc;
A=[1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8]
result = matrix_change(A,2,2);
result*2*2
result
图示:
matrix_change(X,m1,n1)
X:即为输入的原始矩阵;
分成m1*n1的图块求均值;
PS:matlab的reshape函数配合sum,转置,mean等函数对于矩阵的变换很强大,有些东西自己可以试试,函数就这些,但用法很多。