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  • C#实现字符串去重

    方法一 注:需要.net 3.5框架的支持

    string s = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
    s = string.Join(",", s.Split(',').Distinct().ToArray());

    方法二

    class Program
    {
    static void Main(string[] args)
    {
    string result="";
    string str = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
    ArrayList list = array(str);
    for (int i = 0; i < list.Count;i++)
    {
    if (i == list.Count - 1)
    {
    result += list[i];
    }
    else
    {
    result += list[i] + ",";
    }
    }
    Console.WriteLine(result);

    Console.ReadKey();
    }

    static ArrayList array(string str)
    {
    ArrayList aimArr = new ArrayList();
    ArrayList strArr = new ArrayList();
    string [] strs=str.Split(',');
    foreach (string s in strs)
    {
    strArr.Add(s);
    }
    for (int i = 0; i < strs.Length; i++)
    {
    if (!aimArr.Contains(strs[i]))
    {
    aimArr.Add(strs[i]);
    }
    }
    return aimArr;
    }
    }

    //101,102,103,104,105,106,107,108

    方法三:使用正则

                string input = "101,102,103,104,105,101,102,103,104,105,106,107,101,108";
    input = Regex.Replace(input + ",", @"(?:([^,]+,))(?=.*?\1)", "");
    Console.WriteLine(input.Substring(0,input.Length-1));



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  • 原文地址:https://www.cnblogs.com/superfeeling/p/2399992.html
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