HDU 1020 Encoding 模拟

Encoding

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 39047    Accepted Submission(s): 17279

Problem Description

Given a string containing only 'A' - 'Z', we could encode it using the following method: 

1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.

2. If the length of the sub-string is 1, '1' should be ignored.

 

Input

The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only 'A' - 'Z' and the length is less than 10000.

 

Output

For each test case, output the encoded string in a line.

 

Sample Input

2 ABC ABBCCC

 

Sample Output

ABC A2B3C

水题，直接按照题意模拟就行

#include<iostream>
#include<stdio.h>
#include<string.h>
#include<queue>
#include<vector>
using namespace std;
struct Node
{
    char a;
    int num;
};
vector<Node> q;

int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        q.clear();
        char ch[10005];
        scanf("%s",ch);
        int len=strlen(ch);
        Node tmp;
        tmp.a=ch[0];
        tmp.num=1;
        for(int i=1;i<len;i++)
        {
            if(ch[i]==tmp.a) tmp.num++;
            else
            {
                q.push_back(tmp);
                tmp.a=ch[i];
                tmp.num=1;
            }
        }
        q.push_back(tmp);
        for(int i=0;i<q.size();i++)
        {
            if(q[i].num>1)
            {
                printf("%d%c",q[i].num,q[i].a);
            }
            else printf("%c",q[i].a);
        }
        printf("
");
    }
    return 0;
}