zoukankan      html  css  js  c++  java
  • hdu 1159 Common Subsequence

    Common Subsequence

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 33719    Accepted Submission(s): 15340


    Problem Description
    A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk> is a subsequence of X if there exists a strictly increasing sequence <i1, i2, ..., ik> of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = <a, b, f, c> is a subsequence of X = <a, b, c, f, b, c> with index sequence <1, 2, 4, 6>. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y. 
    The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line. 
     
    Sample Input
    abcfbc abfcab programming contest abcd mnp
     
    Sample Output
    4 2 0
    #include<iostream>
    #include<stdio.h>
    #include<string>
    #include<string.h>
    using namespace std;
    int main(){
        char s1[1000];
        char s2[1000];
        while(~scanf("%s%s",s1,s2)){
            int dp[1005][1005];
            int n=strlen(s1);
            int m=strlen(s2);
            for(int i=0;i<n;i++)
            {
                for(int j=0;j<m;j++){
                    if(s1[i]==s2[j]){
                        dp[i+1][j+1]=dp[i][j]+1;
                    }else{
                        dp[i+1][j+1]=max(dp[i+1][j],dp[i][j+1]);
                    }
                }
            }
            printf("%d
    ",dp[n][m]);
        }
        return 0;
    }
    View Code
  • 相关阅读:
    最强PostMan使用教程
    Fiddler模拟post四种请求数据
    关于Spring集成Quartz的concurrent属性
    数据事务四种隔离机制和七种传播行为
    eclipse properties 文件查看和编辑插件
    RabbitMq的整理 exchange、route、queue关系
    MySQL关闭查询缓存(QC)的两种方法
    Map集合的四种遍历方式
    springBoot使用外部Tomcat启动项目
    解决tomcat闪退问题
  • 原文地址:https://www.cnblogs.com/superxuezhazha/p/5705320.html
Copyright © 2011-2022 走看看