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  • layui动态生成下拉列表

    <select name="deptmgr" lay-filter="FirstSelect" id="FirstSelect" lay-search="">
                        <#--此处动态生成select-->
                        </select>
    
    
    --------------------------------------------------------------
    //监听头部工具事件
    table.on("toolbar(deptTable)", function (obj) {
    switch (obj.event) {
    case 'add':
    var FirstSelect = $("#FirstSelect");
    commonFun.loadDeptSelect(FirstSelect);//加载后台数据,渲染select
    openAddFirstDept();//打开添加一级部门弹出层
    break;
    case 'batchDelete':
    layer.confirm('真的删除么?<br/>(含有子部门的将无法删除...)', function (index) {
    layer.close(index);
    //向服务端发送删除指令
    batchDeleteDept();//执行批量删除函数
    });
    break;
    }
    ;
    });
    ------------------------------------------------------------ 
    //加载后台数据,渲染到select中
    var commonFun = {
    //canshu:要渲染的select的jquery对象
    loadDeptSelect: function (canshu, mgr) {

    var option = "<option value = ''>请选择</option>";
    $.post("getComEmp", {'oldDeptmgr': mgr}, function (res) {

    console.log(res);
    console.log(mgr);

    for (i = 0; i < res.length; i++) {

    option += "<option value = '" + res[i].empno + "' ";
    if (res[i].empno == mgr) {
    option += "selected";
    }
    option += ">" + res[i].empname + "</option>";
    canshu.html(option);
    }
    form.render('select');//重新渲染select
    }, "json");
    }
    };
    ------------------------------------------------------
    //控制层
    //获取普通员工和当前部门经理的的信息--普通员工,职位编号为016
    @RequestMapping("/getComEmp")
    @ResponseBody
    public List<Emp> getComEmp(String oldDeptmgr) {

    EmpExample example = new EmpExample();
    EmpExample.Criteria criteria = example.createCriteria();
    criteria.andPosinoEqualTo("016");
    List<Emp> emps = null;
    Emp nowMgr = null;
    try {
    //查询当前部门是否存在部门经理
    nowMgr = empService.selectByPrimaryKey(oldDeptmgr);
    //System.out.println("查询当前部门是否存在部门经理:" + nowMgr);
    emps = empService.selectByExample(example);
    if (nowMgr != null) {
    emps.add(nowMgr);
    }
    } catch (Exception e) {
    e.printStackTrace();
    }
    return emps;
    }
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  • 原文地址:https://www.cnblogs.com/svipero/p/12830644.html
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