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  • 软件测试(四)——Graph Coverage 作业

    题目源程序

     1     public static void printPrimes (int n) 
     2     { 
     3         int curPrime; // Value currently considered for primeness 
     4         int numPrimes; // Number of primes found so far. 
     5         boolean isPrime; // Is curPrime prime? 
     6         int [] primes = new int [MAXPRIMES]; // The list of prime numbers. 
     7         
     8         // Initialize 2 into the list of primes. 
     9         primes [0] = 2; 
    10         numPrimes = 1; 
    11         curPrime = 2; 
    12         while (numPrimes < n) 
    13         { 
    14             curPrime++; // next number to consider ... 
    15             isPrime = true; 
    16             for (int i = 0; i <= numPrimes-1; i++) 
    17             { // for each previous prime. 
    18                 if (isDivisible(primes[i], curPrime)) 
    19                 { // Found a divisor, curPrime is not prime. 
    20                     isPrime = false; 
    21                     break; // out of loop through primes. 
    22                 } 
    23             } 
    24             if (isPrime) 
    25             { // save it! 
    26                 primes[numPrimes] = curPrime; 
    27                 numPrimes++; 
    28             } 
    29         } // End while 
    30         
    31         // Print all the primes out. 
    32         for (int i = 0; i <= numPrimes-1; i++) 
    33         { 
    34             System.out.println ("Prime: " + primes[i]); 
    35         } 
    36     } // end printPrimes
    printPrimes()

    1.CFG控制流图

    2.

    当将MAXPRIMES设置为3或4时。t2=(n=5)会因为越界而出现错误。但是t1=(n=3)不会越界

    3.

    即通过CFG中(2,12)这条edge。n=1即可满足

    4.

    Node Coverage

    TR= {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16}

    Edge Coverage

    TR= {(1,2),(2,3),(3,4),(4,5),(5,6),(6,7),(7,5),(6,8),(8,9),(5,9),

        (9,10),(9,11),(10,11),(11,12),(2,12),(12,13),(13,16),(13,14),(14,15),(15,13)}

    Prime path Coverage

    TR= {[1,2,3,4,5,6,8,9,10,11],[1,2,3,4,5,6,8,9,11],[1,2,3,4,5,6,7],[1,2,3,4,5,9,10,11],[1,2,3,4,5,9,11],[1,2,12,13,16],[1,2,12,13,14,15],

    [2,3,4,5,6,8,9,10,11,2],[2,3,4,5,6,8,9,11,2],[2,3,4,5,9,10,11,2],[2,3,4,5,9,11,2],

    [3,4,5,6,8,9,10,11,2,12,13,16],[3,4,5,6,8,9,10,11,2,12,13,14,15],[3,4,5,6,8,9,11,2,12,13,16],[3,4,5,6,8,9,11,12,13,14,15],[3,4,5,9,10,11,2,12,13,16],[3,4,5,9,10,11,2,12,13,14,15],[3,4,5,9,11,2,12,13,16],[3,4,5,9,11,2,12,13,14,15],[3,4,5,6,8,9,10,11,2,3],[3,4,5,6,8,9,11,2,3],[3,4,5,9,10,11,2,3],[3,4,5,9,11,2,3],

    [4,5,6,8,9,10,11,2,3,4],[4,5,6,8,9,11,2,3,4],[4,5,9,10,11,2,3,4],[4,5,9,11,2,3,4],

    [5,6,8,9,10,11,2,3,4,5],[5,6,8,9,11,2,3,4,5],[5,9,10,11,2,3,4,5],[5,9,11,2,3,4,5],[5,6,7,5],

    [6,8,9,10,11,2,3,4,5,6],[6,8,9,11,2,3,4,5,6],[6,7,5,6],[6,7,5,9,10,11,2,3,4,5,6],[6,7,5,9,11,2,3,4,5,6],[6,7,5,9,10,11,2,12,13,16],[6,7,5,9,10,11,2,14,15],[6,7,5,9,11,2,12,13,16],[6,7,5,9,11,2,14,15],

    [7,5,6,7],[7,5,6,8,9,10,11,2,3,4],[7,5,6,8,9,11,2,3,4],[7,5,6,8,9,10,11,2,12,13,16],[7,5,6,8,9,11,2,12,13,16],[7,5,6,8,9,10,11,2,12,13,14,15],[7,5,6,8,9,11,2,12,13,14,15],

    [8,9,10,11,2,3,4,5,6,8],[8,9,11,2,3,4,5,6,8],

    [9,10,11,2,3,4,5,6,8,9],[9,11,2,3,4,5,6,8,9],

    [10,11,2,3,4,5,6,8,9,10],[10,11,2,3,4,5,9,10],

    [11,2,3,4,5,6,8,9,10,11],[11,2,3,4,5,9,10,11],[11,2,3,4,5,6,8,9,11],[11,2,3,4,5,9,11],

    [13,14,15,13],[14,15,13,14],[14,15,13,16],[15,13,14,13],[15,13,16]}

    5. Junit进行主路径覆盖测试

     这里要将console的输出结果,重定向到一个数组中

     1 package com.Primes;
     2 
     3 import java.io.ByteArrayOutputStream;
     4 import java.io.PrintStream;
     5 
     6 import junit.framework.TestCase;
     7 
     8 public class PrimesTest extends TestCase {
     9 
    10     private Primes prime = null;
    11     PrintStream console = null;          // 声明(为null):输出流 (字符设备) console
    12     ByteArrayOutputStream bytes = null;  // 声明(为null):bytes 用于缓存console 重定向过来的字符流
    13     
    14     protected void setUp() throws Exception {
    15         super.setUp();
    16         prime = new Primes();
    17         bytes = new ByteArrayOutputStream();    // 分配空间
    18         console = System.out;                   // 获取System.out 输出流的句柄
    19         System.setOut(new PrintStream(bytes));  // 将原本输出到控制台Console的字符流 重定向 到 bytes
    20     }
    21 
    22     protected void tearDown() throws Exception {
    23         super.tearDown();
    24         System.setOut(console);
    25     }
    26 
    27     public void testPrintPrimes() {
    28         String s = new String("Prime: 2
    Prime: 3
    Prime: 5
    ");    // 注意:控制台的换行,这里用 '
    ' 表示
    29         prime.printPrimes(3);
    30         assertEquals(s, bytes.toString());          // bytes.toString() 作用是将 bytes内容 转换为字符流
    31     }
    32 
    33 }
    PrimesTest

    结果:

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  • 原文地址:https://www.cnblogs.com/sywang/p/5335369.html
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