zoukankan      html  css  js  c++  java
  • hdoj 3065 病毒侵袭持续中(AC自动机)

    题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3065

    思路分析:问题需要模式匹配多个模式串,需要注意的是模式串会包含和重叠,需要对AC自动机的匹配过程进行修改,对于每个节点,需要从该节点的失败指针回溯,

    如果失败指针回溯后的节点为某个模式串的最后一个节点,则匹配了另一个模式串;

    代码如下:

    #include <queue>
    #include <cstdio>
    #include <cstring>
    #include <iostream>
    #include <algorithm>
    using namespace std;
    
    const int KIND = 128;
    const int MAX_NODE = 1020 * 50;
    const int MAX_N = 1000 + 10;
    const int MAX_M = 2000000 + 100;
    char str[MAX_M];
    int visited[MAX_N];
    int vir_match[MAX_N];
    char vir[MAX_N][60];
    
    struct Trie {
        int root, count;
        int next[MAX_NODE][KIND], fail[MAX_NODE], end[MAX_NODE];
        void Init()
        {
            count = 0;
            root = NewNode();
        }
        int NewNode()
        {
            for (int i = 0; i < KIND; ++i)
                next[count][i] = -1;
            end[count] = -1;
            return count++;
        }
    
        void Insert(char *str, int id)
        {
            int i = 0, k = 0;
            int now = root;
    
            while (str[i])
            {
                k = str[i];
                if (next[now][k] == -1)
                    next[now][k] = NewNode();
                now = next[now][k];
                ++i;
            }
            end[now] = id;
        }
    
        void BuildAutomaton()
        {
            queue<int> Q;
    
            fail[root] = -1;
            Q.push(root);
            while (!Q.empty())
            {
                int now = Q.front();
                int p = -1;
                Q.pop();
    
                for (int i = 0; i < KIND; ++i)
                {
                    if (next[now][i] != -1)
                    {
                        if (now == root)
                            fail[next[now][i]] = root;
                        else
                        {
                            p = fail[now];
                            while (p != -1)
                            {
                                if (next[p][i] != -1)
                                {
                                    fail[next[now][i]] = next[p][i];
                                    break;
                                }
                                p = fail[p];
                            }
                            if (p == -1)
                                fail[next[now][i]] = root;
                        }
                        Q.push(next[now][i]);
                    }
                }
            }
        }
    
        int Match(char *str)
        {
            int i = 0, k = 0, vir_count = 0;
            int p = root;
    
            while (str[i])
            {
                k = str[i];
                while (next[p][k] == -1 && p != root)
                    p = fail[p];
                p = next[p][k];
                p = (p == -1) ? root : p;
    
                int temp = p;
                while (temp != root)
                {
                    if (end[temp] != -1)
                    {
                        if (visited[end[p]] == 0)
                            vir_match[vir_count++] = end[p];
                        visited[end[p]]++;
                    }
                    temp = fail[temp];
                }
                ++i;
            }
            return vir_count;
        }
    };
    Trie root;
    
    int main()
    {
        int vir_num = 0;
        int match_count = 0;
    
        while (scanf("%d
    ", &vir_num) != EOF)
        {
            root.Init();
            memset(vir_match, 0, sizeof(vir_match));
            memset(visited, 0, sizeof(visited));
            for (int i = 0; i < vir_num; ++i)
            {
                gets(str);
                strcpy(vir[i], str);
                root.Insert(str, i + 1);
            }
    
            match_count = 0;
            root.BuildAutomaton();
            gets(str);
            int ans = root.Match(str);
            sort(vir_match, vir_match + ans);
            if (ans)
            {
                for (int j = 0; j < ans - 1; ++j)
                    printf("%s: %d
    ", vir[vir_match[j] - 1], visited[vir_match[j]]);
                printf("%s: %d
    ", vir[vir_match[ans - 1] - 1],
                    visited[vir_match[ans - 1]]);
            }
        }
        return 0;
    }
  • 相关阅读:
    python批量安装包文件requirements.txt
    python→列表、元组、字典、集合对比整理表
    Python ddt+xlrd的使用
    input类型上传多个文件(selenium+Python)
    iframe切入切出问题,经常会碰到
    selenium+python 第一步启动火狐报错解决方案,已成功
    QTP从svn上载下来无法跑,解决
    函数可变参传值(python)
    关于python 函数参数
    Air Kiss
  • 原文地址:https://www.cnblogs.com/tallisHe/p/4666084.html
Copyright © 2011-2022 走看看