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  • oracle 行转列,列转行

    [一]、行转列

    1.1、初始测试数据

    表结构:TEST_TB_GRADE

    create table TEST_TB_GRADE   
    (   
      ID        NUMBER(10) not null,   
    
      USER_NAME VARCHAR2(20 CHAR),   
    
      COURSE    VARCHAR2(20 CHAR),   
    
      SCORE     FLOAT  
    
    )  

     初始数据如下图:

                            

    1.2、 如果需要实现如下的查询效果图:

                         

    这就是最常见的行转列,主要原理是利用decode函数、聚集函数(sum),结合group by分组实现的,具体的sql如下:

    select t.user_name,   
    sum(decode(t.course, '语文', score,null)) as CHINESE,   
    sum(decode(t.course, '数学', score,null)) as MATH,   
    sum(decode(t.course, '英语', score,null)) as ENGLISH   
    from test_tb_grade t   
    group by t.user_name   
    order by t.user_name  

    1.3、延伸

    如果要实现对各门功课的不同分数段进行统计,效果图如下:

                     

    select t2.SCORE_GP,
      sum(decode(t2.course, '语文', COUNTNUM,null)) as CHINESE,
      sum(decode(t2.course, '数学', COUNTNUM,null)) as MATH,
      sum(decode(t2.course, '英语', COUNTNUM,null)) as ENGLISH
    from (
      select t.course,
             case when t.score  <60 then '00-60'
                  when t.score >=60 and t.score <80  then '60-80'
                  when t.score >=80 then '80-100' end as SCORE_GP,
             count(t.score) as COUNTNUM
      FROM test_tb_grade t
      group by t.course, 
            case when t.score  <60  then '00-60'
                  when t.score >=60 and t.score <80  then '60-80'
                  when t.score >=80 then '80-100' end
      order by t.course ) t2
    group by t2.SCORE_GP
    order by t2.SCORE_GP
     

    [二]、列转行

    1.1、初始测试数据

            表结构:TEST_TB_GRADE2

    create table TEST_TB_GRADE2   
    (   
      ID         NUMBER(10) not null,   
      USER_NAME  VARCHAR2(20 CHAR),   
      CN_SCORE   FLOAT,   
      MATH_SCORE FLOAT,   
      EN_SCORE   FLOAT  
    )

     初始数据如下图:


            

    1.2、 如果需要实现如下的查询效果图:


                           

    这就是最常见的列转行,主要原理是利用SQL里面的union,具体的sql语句如下:

    select user_name, '语文' COURSE , CN_SCORE as SCORE from test_tb_grade2    
    union select user_name, '数学' COURSE, MATH_SCORE as SCORE from test_tb_grade2    
    union select user_name, '英语' COURSE, EN_SCORE as SCORE from test_tb_grade2    
    order by user_name,COURSE  

     也可以利用【 insert all into ... select 】来实现,首先需要先建一个表TEST_TB_GRADE3:

    create table TEST_TB_GRADE3     
        (    
          USER_NAME VARCHAR2(20 CHAR),     
          COURSE    VARCHAR2(20 CHAR),     
          SCORE     FLOAT     
        )    

    再执行下面的sql:

    insert all  
    into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '语文', CN_SCORE)   
    into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '数学', MATH_SCORE)   
    into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '英语', EN_SCORE)   
    select user_name, CN_SCORE, MATH_SCORE, EN_SCORE from test_tb_grade2;   
    commit;  

     别忘记commit操作,然后再查询TEST_TB_GRADE3,发现表中的数据就是列转成行了。

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  • 原文地址:https://www.cnblogs.com/tanlei-sxs/p/9639132.html
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