题目描述:
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example:
Input: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3 Output: [1,2,2,3,5,6]
代码实现:
1 class Solution(object): 2 def merge(self, nums1, m, nums2, n): 3 """ 4 :type nums1: List[int] 5 :type m: int 6 :type nums2: List[int] 7 :type n: int 8 :rtype: None Do not return anything, modify nums1 in-place instead. 9 """ 10 while m > 0 and n > 0: 11 if nums1[m-1] >= nums2[n-1]: 12 nums1[m+n-1] = nums1[m-1] 13 m -= 1 14 else: 15 nums1[m+n-1] = nums2[n-1] 16 n -= 1 17 if n > 0: 18 nums1[:n] = nums2[:n]