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  • 以lambda形式优化结构 分类: python 小练习 divide into python python基础学习 2013-12-30 21:07 279人阅读 评论(0) 收藏

    #coding:utf-8
    import re
    '''
    以lambda函数形式将这些函数的内容直接嵌入rules列表本身
    '''
    rules=
    (
    (lambda word:re.search('[sxz]$',word),
    lambda word:re.sub('$','es',word)),
    
    (lambda word:re.search('[^aeioudgkprt]h$',word),
    lambda word:re.sub('$','es',word)),
    
    (lambda word:re.search('[^aeiou]y$',word),
    lambda word:re.sub('y$','ies',word)),
    
    (lambda word:re.search('$',word),
    lambda word:re.sub('$','s',word))
    
    )
    
    def plural(noun):
        for matchesRule,applyRule in rules:
            if matchesRule(noun):
                return applyRule(noun)
    if __name__ == '__main__':
        main()
    


    进一步优化:

    #coding:utf-8
    import re
    def buildMatchAndApllyFunctions((pattern,search,replace)):#参数是一个元组
        matchFunction=lambda word:re.search(pattern,word)
        applFunction=lambda word:re.sub(search,replace,word)
        return matchFunction,applFunction
    
    patterns=
    (
    #注意此处使用的是包括三个元素的元组
    ('[szx]$','$','es'),
    ('[^aeioudgkprt]h$','$','es'),
    ('(qu|[^aeiou])y$','y$','ies'),
    ('$','$','s')
    )
    
    rules=map(buildMatchAndApllyFunctions,patterns)
    
    def plural(noun):
        for matchesRule,applyRule in rules:
            if matchesRule(noun):
                return applyRule(noun)
    
    if __name__ == '__main__':
        plural(noun)
    
    



    版权声明:本文为博主原创文章,未经博主允许不得转载。

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  • 原文地址:https://www.cnblogs.com/think1988/p/4627979.html
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