zoukankan      html  css  js  c++  java
  • HDU 2509 Be the Winner

    Be the Winner

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1291    Accepted Submission(s): 667

    Problem Description
    Let's consider m apples divided into n groups. Each group contains no more than 100 apples, arranged in a line. You can take any number of consecutive apples at one time. For example "@@@" can be turned into "@@" or "@" or "@ @"(two piles). two people get apples one after another and the one who takes the last is the loser. Fra wants to know in which situations he can win by playing strategies (that is, no matter what action the rival takes, fra will win).
     
    Input
    You will be given several cases. Each test case begins with a single number n (1 <= n <= 100), followed by a line with n numbers, the number of apples in each pile. There is a blank line between cases.
     
    Output
    If a winning strategies can be found, print a single line with "Yes", otherwise print "No".
     
    Sample Input
    2
    2 2
    1
    3
     
    Sample Output
    No
    Yes
     
    Source
     
    Recommend
    lcy
     
     
    和上一题,一样的。。。。。。⊙﹏⊙
     
    #include<stdio.h>
    int f[102];
    int main()
    {
        int i,n,m,num1,num2;
        while(scanf("%d",&n)>0)
        {
            m=0;num1=0;num2=0;
            for(i=1;i<=n;i++)
            {
                scanf("%d",&f[i]);
                m=m^f[i];
                if(f[i]==1)num1++;
                if(f[i]>1) num2++;
            }
            if(m==0)
            {
                if(num2>=2)
                    printf("No\n");
                else printf("Yes\n");
            }
            if(m>0)
            {
                if(num1==n)
                    printf("No\n");
                else printf("Yes\n");
            }
        }
        return 0;
    }
  • 相关阅读:
    hadoop——数据清洗测试
    本地配置hadoop
    从textarea中获取数据后按原样显示
    form自动提交
    艺术和代码的结合 turtle + python 的结合
    python-->微信支付
    python-图片流传输(url转换二维码)
    python-qrcode-二维码
    Java 通过先序中序序列生成二叉树
    Java 实现二叉树的构建以及3种遍历方法
  • 原文地址:https://www.cnblogs.com/tom987690183/p/3104118.html
Copyright © 2011-2022 走看看