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  • Java for LeetCode 112 Path Sum

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

    For example:
    Given the below binary tree and sum = 22,

                  5
                 / 
                4   8
               /   / 
              11  13  4
             /        
            7    2      1
    

    return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

    解题思路:

    递归,JAVA实现如下:

        public boolean hasPathSum(TreeNode root, int sum) {
            if(root==null)
            	return false;
        	if(root.val==sum&&root.left==null&&root.right==null)
            	return true;
            else return hasPathSum(root.left,sum-root.val)||hasPathSum(root.right,sum-root.val);
        }
    
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  • 原文地址:https://www.cnblogs.com/tonyluis/p/4524816.html
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