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  • Oracle:指定时间范围内的周分组输出.

    今日QQ群有人询问 “
     大家好,我最近接到一项任务,在给定的数据库中添加 周 字段,一致为2000-01-01~2020-12-31的日期字段
       已知
       大家能提点意见吗?谢谢
    结果类似下图,本着为以后不会忘记这个问题的想法,记录一下SQL.PS: 周六开始为1周起点,周五为周末。


    /* Formatted on 11/23/2011 2:35:33 PM (QP5 v5.163.1008.3004) */
    WITH src
    AS (SELECT TRUNC (DATE '2000-1-1') fromdate,
    TRUNC (DATE '2001-2-1') todate
    FROM DUAL),
    dataset
    AS ( SELECT LEVEL AS seq
    FROM DUAL
    CONNECT BY LEVEL < (SELECT todate - fromdate FROM src)),
    datawithindices
    AS (SELECT src.*,
    dataset.*,
    CASE TO_CHAR (fromdate + seq - 1, 'DY')
    WHEN 'SAT' THEN 1
    WHEN 'SUN' THEN 2
    WHEN 'MON' THEN 3
    WHEN 'TUE' THEN 4
    WHEN 'WED' THEN 5
    WHEN 'THU' THEN 6
    WHEN 'FRI' THEN 7
    END
    indice
    FROM src, dataset),
    filt
    AS (SELECT seq, fromdate + seq - 1 nowaday, indice FROM datawithindices),
    alldata
    AS (SELECT filt.*, CEIL (indice / 7) + FLOOR (seq / 7) weekno FROM filt)
    SELECT 'WEEK '||weekno week_seq, begindate, enddate
    FROM (SELECT weekno,
    FIRST_VALUE (nowaday)
    OVER (PARTITION BY weekno ORDER BY weekno)
    begindate,
    LAST_VALUE (nowaday)
    OVER (PARTITION BY weekno ORDER BY weekno)
    enddate,
    ROW_NUMBER () OVER (PARTITION BY weekno ORDER BY weekno) rn
    FROM alldata)
    WHERE rn = 1


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  • 原文地址:https://www.cnblogs.com/tracy/p/2260314.html
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