一、技术总结
- 分三种情况:
- 当
二、参考代码
#include<iostream>
using namespace std;
int main(){
int n, a = 1, ans = 0;
int left, now, right;
cin >> n;
while(n / a != 0){
left = n / (a * 10);
now = n / a % 10;
right = n % a;
if(now == 0) ans += left * a;
else if(now == 1) ans += left * a + right + 1;
else ans += (left + 1) * a;
a *= 10;
}
printf("%d
", ans);
return 0;
}