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  • UVa 11324

    题目链接:https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=0&problem=2299&mosmsg=Submission+received+with+ID+26582032

    缩点以后求最长路,拓扑和记搜都可以

    一定要注意所开数组的大小,边的数组不要开成点的,因为数组开小 WA 了一个小时,实在不行就把数组使劲往大开

    #include<bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    
    const int maxn = 1010;
    
    int T, n, m;
    int u[50010], v[50010], in[maxn];
    
    vector<int> G[maxn];
    int h[maxn], cnt = 0;
    struct E{
    	int to, next;
    }e[50010];
    void add(int u, int v){
    	e[++cnt].to = v;
    	e[cnt].next = h[u];
    	h[u] = cnt;
    }
    
    int low[maxn], st[maxn], sccno[maxn], sz[maxn], dfn = 0, scc_cnt = 0;
    
    stack<int> S;
    
    void dfs(int u){
    	low[u] = st[u] = ++dfn;
    	S.push(u);
    	
    	for(int i = h[u] ; i != -1 ; i = e[i].next){
    		int v = e[i].to;
    		if(!st[v]){
    			dfs(v);
    			low[u] = min(low[u], low[v]);
    		} else if(!sccno[v]){
    			low[u] = min(low[u], st[v]);
    		}
    	}
    	
    	if(low[u] == st[u]){
    		++scc_cnt;
    		for(;;){
    			int x = S.top(); S.pop();
    			sccno[x] = scc_cnt;
    			++sz[scc_cnt];
    			if(x == u) break;
    		}
    	}
    }
    
    void tarjan(){
    	memset(low, 0, sizeof(low));
    	memset(st, 0, sizeof(st));
    	memset(sccno, 0, sizeof(sccno));
    	dfn = 0, scc_cnt = 0;
    	
    	for(int i = 1 ; i <= n ; ++i){
    		if(!st[i]) dfs(i);
    	}
    }
    
    int dp[maxn];
    vector<int> path;
    
    void topo(){
    	queue<int> q;
    	path.clear(); memset(dp, 0, sizeof(dp));
    	
    	for(int i = 1 ; i <= scc_cnt ; ++i){
    		if(!in[i]){
    			q.push(i);
    			dp[i] = sz[i];
    			path.push_back(i);
    		}
    	}
    	
    	while(!q.empty()){
    		int u = q.front(); q.pop();
    		for(int i = h[u] ; i != -1 ; i = e[i].next){
    			int v = e[i].to;
    			--in[v];
    			if(!in[v]){
    				q.push(v);
    				path.push_back(v);
    			}
    		}
    	}
    	
    	for(auto u : path){
    		for(int i = h[u] ; i != -1 ; i = e[i].next){
    			int v = e[i].to;
    			dp[v] = max(dp[v], dp[u] + sz[v]);
    		}
    	}
    }
    
    
    int DP(int u){
    	if(dp[u] >= 0) return dp[u];
    	dp[u] = sz[u];
    	for(int i = h[u] ; i != -1 ; i = e[i].next){
    		int v = e[i].to;
    		dp[u] = max(dp[u], DP(v) + sz[u]);
    	}
    	return dp[u];
    }
    
    ll read(){ ll s = 0, f = 1; char ch = getchar(); while(ch < '0' || ch > '9'){ if(ch == '-') f = -1; ch = getchar(); } while(ch >= '0' && ch <= '9'){ s = s * 10 + ch - '0'; ch = getchar(); } return s * f; }
    
    int main(){
    	scanf("%d", &T);
    	while(T--){
    		memset(in, 0, sizeof(in));
    		memset(h, -1, sizeof(h)); cnt = 0;
    		memset(sz, 0, sizeof(sz));
    		scanf("%d%d", &n, &m);
    				
    		for(int i = 1 ; i <= m ; ++i){
    			scanf("%d%d", &u[i], &v[i]);
    			add(u[i], v[i]);
    		}
    
        memset(sz, 0, sizeof(sz));
        tarjan();
    
     	memset(h, -1, sizeof(h)); cnt = 0; 
    	for(int i = 1 ; i <= m ; ++i){
    		if(sccno[u[i]] != sccno[v[i]]){
    			add(sccno[u[i]], sccno[v[i]]);
    			++in[sccno[v[i]]];
    		}
    	}
    
        int ans = 0;
        topo();
        for(int i = 1 ; i <= n ; ++i) ans = max(ans, dp[i]);
    //    memset(dp, -1, sizeof(dp)); 
    //    for(int i = 1; i <= scc_cnt; i++) ans = max(ans, DP(i));
     
        printf("%d
    ", ans);
    }
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/tuchen/p/15024813.html
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