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  • 字符串解析

    问题描述: 

    代码实现:

     1 package xiaoMiBishi_2015;
     2 
     3 import java.util.*;
     4 
     5 public class xiaoMi_2015 {
     6     
     7     public static void main(String[] args){
     8         int[] A,B,Key; String t_source;
     9         int max1,max2;             //记录x幂的最大值
    10         max1=0; max2=0;
    11         Scanner b=new Scanner(System.in);
    12         t_source=b.nextLine();
    13         b.close();
    14         A=new int[100];
    15         B=new int[100];
    16         Key=new int[100];
    17         for( int i=0;i<100;i++)
    18             {A[i]=0;B[i]=0;Key[i]=0;}
    19         String[] T=t_source.split(" ");
    20         String[] t=T[0].split(",");
    21         String[] u=T[1].split(",");
    22         
    23         for(int i=0;i<u.length;i=i+2){                          //取得每个i次幂的值放入A[i]
    24             u[i]=u[i].substring(1, u[i].length());        
    25             u[i+1]=u[i+1].substring(0, u[i+1].length()-1);        
    26             int n=Integer.parseInt(u[i]);
    27             B[n]=Integer.parseInt(u[i+1]);
    28             if(n>=max2)
    29             max2=n;
    30         }
    31         
    32         for(int i=0;i<t.length;i=i+2){                          //取得每个i次幂的值放入B[i]
    33             t[i]=t[i].substring(1, t[i].length());        
    34             t[i+1]=t[i+1].substring(0, t[i+1].length()-1);        
    35             int n=Integer.parseInt(t[i]);
    36             A[n]=Integer.parseInt(t[i+1]);
    37             if(n>=max1)
    38                 max1=n;
    39         }
    40         
    41         //System.out.print(max1);
    42         //System.out.print(max2);
    43         
    44        for(int p=0;p<=max1+max2;p++){                        //两者想乘整合
    45                   
    46              for(int q=0;q<=p;q++){
    47                  
    48                        Key[p]=Key[p]+A[q]*B[p-q];
    49                          
    50                      }
    51         
    52              System.out.println(Key[p]);
    53          }
    54        
    55        System.out.println("结果是:");                        //输出结果
    56         int n=0;                                           
    57         for(int i=max1+max2;i>=0;i--){
    58             
    59             if(Key[i]!=0){
    60                 if(n!=0 && Key[i]>0)
    61                 System.out.print("+");
    62                 System.out.print(Key[i]);
    63                 System.out.print("x^");
    64                 System.out.print(i);
    65                 n++;
    66             }
    67             
    68         }
    69     }
    70 
    71 }

    运行效果:

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  • 原文地址:https://www.cnblogs.com/udld/p/4096695.html
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