获取某个时间开始 之后的 N次[周几,周几]

废话不多说，直接上菜！

调用函数代码举例

                        //PS :这里需要注意的是 周日 是 0 ！！！！！

                        console.log(getBeforeDate(-10000)) //一万天之后的日期
			console.log(getWeek('2019-07-03',[2,3],20))//从'2019-07-03' 开始获取之后 20 个 周二、周三的日期

JS代码

/**
 * 获取某个时间开始 之后的 N次[周几,周几]
 * @param {Object} begin 开始时间
 * @param {Object} week_arr 需要获取的周几数组
 * @param {Object} Max 需要获取数组最大长度
 */
 function getWeek (begin, week_arr,Max){
     var dateArr = new Array();
     var stimeArr = begin.split("-");//=>["2018", "01", "01"]
     var etimeArr = getBeforeDate(-10000).split("-");//=>["2018", "01", "30"] 这里我给了一个10000天后的一起可更具需求更改
  
     var stoday = new Date();
     stoday.setUTCFullYear(stimeArr[0], stimeArr[1]-1, stimeArr[2]);
     var etoday = new Date();
     etoday.setUTCFullYear(etimeArr[0], etimeArr[1]-1, etimeArr[2]);
  
     var unixDb = stoday.getTime();//开始时间的毫秒数
     var unixDe = etoday.getTime();//结束时间的毫秒数
  
     for (var k = unixDb; k <= unixDe;) {
     	//达到最大次数时,结束循环
     	if(dateArr.length==Max){
     		break;
     	}else{
     		let needJudgeDate = msToDate(parseInt(k)).withoutTime;
	        //不加这个if判断直接push的话就是已知时间段内的所有日期
	        
	        $.each(week_arr, function(i,o) {
	        	if (new Date(needJudgeDate).getDay() === o) {
		            dateArr.push(needJudgeDate);
		        }
	        })
	         k = k + 24*60*60*1000;
     	}
        
     }
     return dateArr;
 }
  
//根据毫秒数获取日期
function msToDate (msec) {
    let datetime = new Date(msec);
    let year = datetime.getFullYear();
    let month = datetime.getMonth();
    let date = datetime.getDate();
    let hour = datetime.getHours();
    let minute = datetime.getMinutes();
    let second = datetime.getSeconds();
  
    let result1 = year +
                 '-' +
                 ((month + 1) >= 10 ? (month + 1) : '0' + (month + 1)) +
                 '-' +
                 ((date + 1) < 10 ? '0' + date : date) +
                 ' ' +
                 ((hour + 1) < 10 ? '0' + hour : hour) +
                 ':' +
                 ((minute + 1) < 10 ? '0' + minute : minute) +
                 ':' +
                 ((second + 1) < 10 ? '0' + second : second);
  
    let result2 = year +
                 '-' +
                 ((month + 1) >= 10 ? (month + 1) : '0' + (month + 1)) +
                 '-' +
                 ((date + 1) < 11 ? '0' + date : date);
  
    let result = {
        hasTime: result1,
        withoutTime: result2
    };
  
    return result;
}




//-----[获取前n天的日期]
function getBeforeDate(n) {
	var n = n;
	var d = new Date();
	var year = d.getFullYear();
	var mon = d.getMonth() + 1;
	var day = d.getDate();
	if(day <= n) {
		if(mon > 1) {
			mon = mon - 1;
		} else {
			year = year - 1;
			mon = 12;
		}
	}
	d.setDate(d.getDate() - n);
	year = d.getFullYear();
	mon = d.getMonth() + 1;
	day = d.getDate();
	s = year + "-" + (mon < 10 ? ('0' + mon) : mon) + "-" + (day < 10 ? ('0' + day) : day);
	return s;
}
//-----[获取前n天的日期END]