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  • 【笔记】DataTable或IList使用GroupBy方法的lamda表达式

    DataTable GroupBy的用法

                var result = dt.AsEnumerable().
                    GroupBy(g => new
                    {
                        StaffID = g.Field<string>("StaffID"),
                        StaffName = g.Field<string>("StaffName"),
                        ActivityDate = g.Field<string>("ActivityDate")
                    }).
                    Select(n => new DailyRouteDisplayItem
                    {
                        ActivityDate = n.Key.ActivityDate,
                        StaffID = n.Key.StaffID,
                        StaffName = n.Key.StaffName,
                        RouteList = n.Select(x => new RouteDisplayItem
                        {
                            StaffID = x["StaffID"].ToString(),
                            StaffName = x["StaffName"].ToString(),
                            ActivityID = x["ActivityID"].ToString(),
                            ActivityDate = x["ActivityDate"].ToString(),
                            CheckinType = x["CheckinType"].ToString(),
                            CheckinTime = x["CheckinTime"].ToString(),
                            CheckinLat = ConvertObject.ToDecimal(x["CheckinLat"]),
                            CheckinLng = ConvertObject.ToDecimal(x["CheckinLng"]),
                            CheckoutType = x["CheckoutType"].ToString(),
                            CheckoutTime = x["CheckoutTime"].ToString(),
                            CheckoutLat = ConvertObject.ToDecimal(x["CheckoutLat"]),
                            CheckoutLng = ConvertObject.ToDecimal(x["CheckoutLng"])
                        }).ToList()
                    }).ToList();
    

      

    数组GroupBy的用法

                var result = list.GroupBy(n => new { n.ActivityDate, n.StaffID, n.StaffName }).Select(n => new DailyRouteDisplayItem
                {
                    ActivityDate = n.Key.ActivityDate,
                    StaffID = n.Key.StaffID,
                    StaffName = n.Key.StaffName,
                    RouteList = n.ToList()
                }).ToList();
    

      



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  • 原文地址:https://www.cnblogs.com/vengen/p/8624170.html
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