HDU 1671 Phone List (字典树)

Phone List

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Description

Given a list of phone numbers, determine if it is consistent in the sense that no number is the prefix of another. Let’s say the phone catalogue listed these numbers:
1. Emergency 911
2. Alice 97 625 999
3. Bob 91 12 54 26
In this case, it’s not possible to call Bob, because the central would direct your call to the emergency line as soon as you had dialled the first three digits of Bob’s phone number. So this list would not be consistent.

 

Input

The first line of input gives a single integer, 1 <= t <= 40, the number of test cases. Each test case starts with n, the number of phone numbers, on a separate line, 1 <= n <= 10000. Then follows n lines with one unique phone number on each line. A phone number is a sequence of at most ten digits.

 

Output

For each test case, output “YES” if the list is consistent, or “NO” otherwise.

 

Sample Input

2

3

911

97625999

91125426

5

113

12340

123440

12345

98346

 

Sample Output

NO

YES

 

题意：给你一些数字的字符串，如果存在一个字符串，它是另一个的前缀，就输出“NO”，否则就“YES”。

分析：用字典树，边插入边检查就行了。

#include<stdio.h>
#include<string.h>

const int MAXN = 10;
const int MAXM = 1000000;
typedef struct TrieNode
{
    bool flag;
    struct TrieNode *next[MAXN];
}TrieNode;

TrieNode Memory[MAXM];
int allocp=0;
bool flag;

void InitTrieRoot(TrieNode **pRoot)
{
    *pRoot=NULL;
}
TrieNode *CreateTrieNode()
{
    TrieNode *p;
    p=&Memory[allocp++];
    p->flag=false;
    for(int i=0;i<MAXN;i++)
        p->next[i]=NULL;
    return p;
}
void InsertTrie(TrieNode **pRoot,char *s)
{
    TrieNode *p;
    if(!(p=*pRoot)) p=*pRoot=CreateTrieNode();
    int i=0,k;
    while(s[i])
    {
        k=s[i++]-'0';
        if(p->next[k])
        {
            if(p->next[k]->flag||s[i]=='')
            {
                flag=false;
                return;
            }
        }
        else p->next[k]=CreateTrieNode();
        p=p->next[k];
    }
    p->flag=true;
}
char str[50];

int main()
{
    int T,n;
    TrieNode *Root=NULL;
    scanf("%d",&T);
    while(T--)
    {
        flag=true;
        allocp=0;
        scanf("%d",&n);
        InitTrieRoot(&Root);
        for(int i=1;i<=n;i++)
        {
            scanf("%s",str);
            if(flag) InsertTrie(&Root,str);
        }
        if(flag) printf("YES
");
        else printf("NO
");
    }
    return 0;
}