在switch中的case语句中声明变量编译的问题
先来看段代码,别管什么意思:
case 10: int i = 0, j = 0; for (i = 0; i < 11; i++) recive_phone[i] = msgbuf.text[i]; recive_phone[i] = ' '; printf("%s文件%s函数%d行:接收端号码:%s ", __FILE__ , __FUNCTION__, __LINE__, recive_phone); for (j = 0; msgbuf.text[i] != ' ' && j < 12; i++,j++) center_phone[j] = msgbuf.text[i]; center_phone[j] = ' '; printf("%s文件%s函数%d行:发送端号码:%s ", __FILE__ , __FUNCTION__, __LINE__, center_phone); break;
我在case:break中声明了变量,结果gcc编译时就提示:
error: a label can only be part of a statement and a declaration is not a statement
有下面三种方法处理:
1、将变量定义放到case：break外面；
2、将case：break中间的语句用{}包含；
case 10: { int i = 0, j = 0; for (i = 0; i < 11; i++) recive_phone[i] = msgbuf.text[i]; recive_phone[i] = ' '; printf("%s文件%s函数%d行:接收端号码:%s ", __FILE__ , __FUNCTION__, __LINE__, recive_phone); for (j = 0; msgbuf.text[i] != ' ' && j < 12; i++,j++) center_phone[j] = msgbuf.text[i]; center_phone[j] = ' '; printf("%s文件%s函数%d行:发送端号码:%s ", __FILE__ , __FUNCTION__, __LINE__, center_phone); } break;
注意case后{}括号
3、在“case：”后面加“；”处理。
case 10: ; int i = 0, j = 0; for (i = 0; i < 11; i++) recive_phone[i] = msgbuf.text[i]; recive_phone[i] = ' '; printf("%s文件%s函数%d行:接收端号码:%s ", __FILE__ , __FUNCTION__, __LINE__, recive_phone); for (j = 0; msgbuf.text[i] != ' ' && j < 12; i++,j++) center_phone[j] = msgbuf.text[i]; center_phone[j] = ' '; printf("%s文件%s函数%d行:发送端号码:%s ", __FILE__ , __FUNCTION__, __LINE__, center_phone); break;