题目:
Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. (Easy)
分析:
不用考虑KMP啥的,就是写好暴力写法就行。
两重循环,注意空串判定,注意haystack比needle长,注意外层循环的终止条件。
代码:
1 class Solution { 2 public: 3 int strStr(string haystack, string needle) { 4 if (haystack.size() == 0 && needle.size() == 0) { 5 return 0; 6 } 7 if (haystack.size() < needle.size()) { 8 return -1; 9 } 10 for (int i = 0; i < haystack.size() - needle.size() + 1; ++i) { 11 int flag = 1; 12 for (int j = 0; j < needle.size(); ++j) { 13 if (haystack[i + j] != needle[j]) { 14 flag = 0; 15 break; 16 } 17 } 18 if (flag == 1) { 19 return i; 20 } 21 } 22 return -1; 23 } 24 };