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  • LKOJ一本通题解报告

    目录

    ·贪心

    ·二分三分

    网页跳转

    解析啥的以后会有的

    贪心目录

    ·T1活动安排

    ·T2种树

    ·T3喷水装置

    ·T4加工生产调度

    ·T5智力大冲浪

    ·练习T1 

    ·练习T2 

    ·练习T3

    ·练习T4

    ·练习T5

    ·练习T6

    二分三分目录

    ·T1数列分段II

    ·T2愤怒的牛

    ·T3扩散

    T1活动安排

     1 /*
     2 problem:yibentong10000
     3 date:2019/4/21
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cstring>
    10 #include<algorithm>
    11 using namespace std;
    12 const int maxn = 1e3+5;
    13 struct node{
    14     int s,f,dif;
    15 };
    16 node a[maxn];
    17 int n,ans;
    18 inline void init(){
    19     cin>>n;
    20     for(int i =1;i <= n;i++)scanf("%d%d",&a[i].s,&a[i].f);
    21 }
    22 inline bool cmp(node x,node y){
    23     return x.f < y.f;
    24 }
    25 int main(){
    26     init();
    27     sort(a+1,a+1+n,cmp);
    28     ans = 1;
    29     int tmp = a[1].f;
    30     for(int i = 2;i <= n;i++)
    31         if(a[i].s >= tmp){
    32             ans++;
    33             tmp = a[i].f;
    34         }
    35     cout<<ans<<endl;
    36     return 0;
    37 }

     T2种树

     1 /*
     2 problem:yibentong10001
     3 date:2019.4.21
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cstring>
    10 #include<algorithm>
    11 using namespace std;
    12 const int maxn = 3e4+5;
    13 struct node{
    14     int b,e,t;
    15 }a[maxn];
    16 int visit[maxn];
    17 int n,ans,h;
    18 inline void init(){
    19     cin>>n;
    20     cin>>h;
    21     for(int i = 1;i <= h;i++)
    22         scanf("%d%d%d",&a[i].b,&a[i].e,&a[i].t);
    23 }
    24 inline bool cmp(node x,node y){
    25     return x.e < y.e;
    26 }
    27 int main(){
    28     init();
    29     sort(a+1,a+1+h,cmp);
    30     for(int i = 1;i <= h;i++){
    31         int cnt = 0;
    32         for(int j = a[i].b;j <= a[i].e;j++)
    33             cnt += visit[j];
    34         if(cnt >= a[i].t)continue;
    35         for(int j = a[i].e;j >= a[i].b;j--)
    36             if(!visit[j]){
    37                 visit[j] = 1;
    38                 cnt++;
    39                 ans++;
    40                 if(cnt == a[i].t)break;
    41             }
    42     }
    43     cout<<ans<<endl;
    44     return 0;
    45 }

     T3喷水装置

     1 /*
     2 problem:yibentong10002
     3 date:2019/4/21
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cstring>
    10 #include<algorithm>
    11 #include<cmath>
    12 using namespace std;
    13 const int maxn = 25e3+5;
    14 struct node{
    15     double head,tail;
    16 }a[maxn];
    17 int n,l,w,T,cnt,ans;
    18 inline bool cmp(node x,node y){
    19     return x.head < y.head;
    20 }
    21 inline void init(){
    22     cin>>n>>l>>w;
    23     cnt = 0;
    24     for(int i = 1,r,position;i <= n;i++){
    25         scanf("%d%d",&position,&r);
    26         if(r <= w/2)continue;
    27         cnt++;
    28         double tmp = r*r-w*w/4.0;
    29         a[cnt].head = position-sqrt(tmp);
    30         a[cnt].tail = position+sqrt(tmp);
    31     }
    32 }
    33 int main(){
    34     cin>>T;
    35     while(T--){
    36         init();
    37         sort(a+1,a+1+cnt,cmp);
    38         ans = 0;
    39         double position = 0;
    40         bool flag = false;
    41         while(position < l){
    42             ans++;
    43             double tmp = position;
    44             for(int i = 1;a[i].head <= tmp && i <= cnt;i++)
    45                 if(position < a[i].tail)
    46                     position = a[i].tail;
    47             if(position == tmp && position < l){
    48                 puts("-1");
    49                 flag = true;
    50                 break;
    51             }
    52         }
    53         if(flag == false)cout<<ans<<endl;
    54     }
    55     return 0;
    56 }

     T4加工生产调度

     1 /*
     2 problem:yibentong10003
     3 date:2019/4/30
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cstring>
    10 #include<algorithm>
    11 #include<cmath>
    12 using namespace std;
    13 const int maxn = 1e3+5;
    14 struct node{
    15     int position,Min;
    16 }p[maxn];
    17 int a[maxn],b[maxn],ans[maxn];
    18 int n;
    19 inline void init(){
    20     cin>>n;
    21     for(int i = 1;i <= n;i++)scanf("%d",&a[i]);
    22     for(int i = 1;i <= n;i++)scanf("%d",&b[i]);
    23     for(int i = 1;i <= n;i++){
    24         p[i].Min = min(a[i],b[i]);
    25         p[i].position = i;
    26     }
    27 }
    28 inline bool cmp(node x,node y){
    29     return x.Min < y.Min;
    30 }
    31 int main(){
    32     init();
    33     sort(p+1,p+1+n,cmp);
    34     int tmph = 0,tmpt = n+1;
    35     for(int i = 1;i <= n;i++)
    36         if(p[i].Min == a[p[i].position]){tmph++;ans[tmph] = p[i].position;}
    37         else{tmpt--;ans[tmpt] = p[i].position;}
    38     int timea = 0,timeb = 0;
    39     for(int i = 1;i <= n;i++){
    40         timea += a[ans[i]];
    41         if(timeb < timea)timeb = timea;
    42         timeb += b[ans[i]];
    43     }
    44     cout<<timeb<<endl;
    45     for(int i = 1;i <= n;i++)printf("%d%c",ans[i],i == n ? '
    ':' ');
    46     return 0;
    47 }

    T5智力大冲浪

     1 /*
     2 problem:yibentong10004
     3 date:2019/4/30
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cstring>
    10 #include<algorithm>
    11 using namespace std;
    12 const int maxn = 5e2+5;
    13 struct node{
    14     int x,y;
    15 }a[maxn];
    16 int vis[5000010];
    17 int flag,s;
    18 int cmp(node a,node b){
    19     return a.y > b.y;
    20 }
    21 int main(){
    22     int m,n;
    23     cin>>m>>n;
    24     for(int i = 1;i <= n;i++)scanf("%d",&a[i].x);
    25     for(int i = 1;i <= n;i++)scanf("%d",&a[i].y);
    26     sort(a+1,a+n+1,cmp);
    27     for(int i = 1;i <= n;i++){
    28         flag = 1;
    29         for(int j = a[i].x;j >= 1;j--)
    30             if(vis[j] == 0){
    31                 flag = 0;
    32                 vis[j] = 1;
    33                 break;
    34             }
    35         if(flag == 1){
    36             for(int k = n;k >= 1;k--)
    37                 if(vis[k] == 0){
    38                     vis[k] = 1;
    39                     break;
    40                 }
    41             s += a[i].y;
    42         }
    43     }
    44     printf("%d
    ",m-s);
    45     return 0;
    46 }

     练习T1数列极差

     1 /*
     2 problem:yibentonglian10000
     3 date:2019/5/5
     4 author:Lonely.Devil
     5 */
     6 
     7 
     8 #include<iostream>
     9 #include<algorithm>
    10 #include<cstdio>
    11 using namespace std;
    12 const int maxn = 1e3+5;
    13 int a[maxn];
    14 int n,Max,Min;
    15 int main(){
    16     cin>>n;
    17     for(int i = 1;i <= n; i++)
    18         scanf("%d",&a[i]);
    19     int tmp;
    20     cin>>tmp;
    21     sort(a+1,a+1+n);
    22     Min = a[n];
    23     for(int i = 1;i < n;i++)
    24         Min = Min*a[n-i]+1;
    25     for(int i = 1;i <= n;i++){
    26         a[i+1] = a[i]*a[i+1]+1;
    27         for(int j = i+1;j < n;j++)
    28             if(a[j] > a[j+1])
    29                 swap(a[j],a[j+1]);
    30     }
    31     Max = a[n];
    32     cout<<Max-Min<<endl;
    33     return 0;
    34 }

    练习T2数列分段

     1 /*
     2 problem:yibentonglian10001
     3 date:2019/5/5
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 using namespace std;
    10 int n,m,ans,now;
    11 int main(){
    12     cin>>n>>m;
    13     for(int i = 1,tmp;i <= n;i++){
    14         scanf("%d",&tmp);
    15         now += tmp;
    16         if(now < m && i == n){
    17             ans++;
    18             break;
    19         }
    20         if(now > m){
    21             ans++;
    22             now = tmp;
    23         }
    24         if(now == m){
    25             ans++;
    26             now = 0;
    27         }
    28     }
    29     cout<<ans<<endl;
    30     return 0;
    31 }

    练习T3线段

     1 /*
     2 problem:yibentonglian10002
     3 date:2019/5/5
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<algorithm>
    10 using namespace std;
    11 const int maxn = 1e6+5;
    12 struct node{
    13     int x,y;
    14 }a[maxn];
    15 int n,now,ans;
    16 inline bool cmp(node a,node b){
    17     return a.y < b.y;
    18 }
    19 int main(){
    20     cin>>n;
    21     for(int i = 1;i <= n;i++)scanf("%d%d",&a[i].x,&a[i].y);
    22     sort(a+1,a+1+n,cmp);
    23     now = a[1].y;
    24     ans = 1;
    25     for(int i = 2;i <= n;i++){
    26         if(a[i].x >= now){
    27             ans++;
    28             now = a[i].y;
    29         }
    30     }
    31     cout<<ans<<endl;
    32     return 0;
    33 }

    练习T4家庭作业

     1 /*
     2 problem:yibentonglian10003
     3 date:2019/5/5
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cstring>
    10 #include<algorithm>
    11 using namespace std;
    12 const int maxn = 1e6+5;
    13 struct node{
    14     int date,val;
    15 }a[maxn];
    16 bool visit[maxn];
    17 bool flag;
    18 int n,ans,s;
    19 inline bool cmp(node a,node b){
    20     return a.val > b.val;
    21 }
    22 int main(){
    23     cin>>n;
    24     for(int i = 1;i <= n;i++)scanf("%d%d",&a[i].date,&a[i].val);
    25     memset(visit,false,sizeof(visit));
    26     sort(a+1,a+1+n,cmp);
    27     for(int i = 1;i <= n;i++){
    28         if(a[i].date <= s)continue;
    29         flag = false;
    30         for(int j = a[i].date;j >= 1;j--)
    31             if(visit[j] == false){
    32                 visit[j] = true;
    33                 ans += a[i].val;
    34                 flag = true;
    35                 break;
    36             }
    37         if(flag == false)s = a[i].date;
    38     }
    39     cout<<ans<<endl;
    40     return 0;
    41 }

    练习T5钓鱼

     1 /*
     2 problem:yibentonglian10004
     3 date:2019/5/5
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<cmath>
    10 using namespace std;
    11 const int maxn = 1e2+5;
    12 int a[maxn],d[maxn],t[maxn],fish[maxn];
    13 int n,ans,h,sum,Max,position;
    14 int main(){
    15     cin>>n>>h;
    16     h *= 12;
    17     for(int i = 1;i <= n;i++)scanf("%d",&a[i]);
    18     for(int i = 1;i <= n;i++)scanf("%d",&d[i]);
    19     for(int i = 1,tmp;i < n;i++)scanf("%d",&tmp),t[i] = t[i-1]+tmp;
    20     for(int i = 1;i <= n;i++){
    21         for(int j = 1;j <= i;j++)fish[j] = a[j];
    22         int time = h - t[i-1];
    23         sum = 0;
    24         for(int j = 1;j <= time;j++){
    25             Max = 0;
    26             for(int k = 1;k <= i;k++)
    27                 if(fish[k] > Max)Max = fish[k],position = k;
    28             if(Max == 0)break;
    29             fish[position] -= d[position];
    30             sum += Max;
    31         }
    32         ans = max(ans,sum);
    33     }
    34     cout<<ans<<endl;
    35     return 0;
    36 }

    练习T6糖果传递

     1 /*
     2 problem:yibentonglian10005
     3 date:2019/5/7
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<algorithm>
    10 #include<cmath>
    11 using namespace std;
    12 const int maxn = 1e6+5;
    13 long long a[maxn],c[maxn];
    14 long long total,ave,ans;
    15 int n;
    16 int main(){
    17     cin>>n;
    18     for(int i = 1;i <= n;i++)scanf("%d",&a[i]),total += a[i];
    19     ave = total/n;
    20     for(int i = 1;i <= n;i++)c[i] = c[i-1]+a[i]-ave;
    21     sort(c+1,c+1+n);
    22     int mid = (n+1)>>1;
    23     for(int i = 1;i <= n;i++)
    24         ans += abs(c[mid]-c[i]);
    25     printf("%lld
    ",ans);
    26     return 0;
    27 }

    T1数列分段II

     1 /*
     2 problem:yibentong10000
     3 date:2019/5/7
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 using namespace std;
    10 const int maxn = 1e5+5;
    11 int a[maxn];
    12 int n,m,l,r;
    13 inline bool check(int x){
    14     int ans = 1,sum = 0;
    15     for(int i = 1;i <= n;i++){
    16         sum += a[i];
    17         if(sum > x)ans++,sum = a[i];
    18     }
    19     if(ans <= m)return true;
    20     return false;
    21 }
    22 int main(){
    23     cin>>n>>m;
    24     int Max = 0,sum = 0;
    25     for(int i = 1;i <= n;i++)scanf("%d",&a[i]),Max = max(Max,a[i]),sum += a[i];
    26     l = Max,r = sum;
    27     while(l <= r){
    28         int mid = (l+r)>>1;
    29         if(check(mid))r = mid-1;
    30         else l = mid+1;
    31     }
    32     cout<<l<<endl;
    33     return 0;
    34 }

    T2愤怒的牛

     1 /*
     2 problem:yibentong10001
     3 date:2019/5/7
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<algorithm>
    10 using namespace std;
    11 const int maxn = 1e5+5;
    12 int a[maxn];
    13 int n,m;
    14 inline bool check(int x){
    15     int ans = 1;
    16     int cnt = a[1]+x;
    17     for(int i = 2;i <= n;i++){
    18         if(a[i] < cnt)continue;
    19         ans++;
    20         cnt = a[i]+x;
    21     }
    22     return ans >= m;
    23 }
    24 int main(){
    25     cin>>n>>m;
    26     for(int i = 1;i <= n;i++)scanf("%d",&a[i]);
    27     sort(a+1,a+1+n);
    28     int l = 0,r = a[n];
    29     while(l <= r){
    30         int mid = (l+r)>>1;
    31         if(check(mid))l = mid+1;
    32         else r = mid-1;
    33     }
    34     cout<<r<<endl;
    35     return 0;
    36 }

     T3扩散

    法一:Kruscal

     1 /*
     2 problem:yibentong10002
     3 date:2019/5/11
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<algorithm>
    10 using namespace std;
    11 #define ll long long
    12 const ll maxn = 5e1+5;
    13 ll father[maxn],x[maxn],y[maxn];
    14 ll n,cnt,sum;
    15 struct edge{
    16     ll x,y,w;
    17 }e[maxn*maxn/2];
    18 ll dist(ll i,ll j){
    19     return (abs(x[i]-x[j])+abs(y[i]-y[j])+1)/2;
    20 }
    21 ll cmp(edge a,edge b){
    22     return a.w < b.w;
    23 }
    24 ll find(ll x){
    25     if(father[x] == x)return x;
    26     else return father[x] = find(father[x]);
    27 }
    28 void Kruscal(){
    29     sort(e+1,e+1+cnt,cmp);
    30     for(ll i = 1;i <= cnt;i++)
    31         if(find(e[i].x) != find(e[i].y)){
    32             father[find(e[i].x)] = find(e[i].y);
    33             sum++;
    34             if(sum == n-1){
    35                 printf("%lld
    ",e[i].w);
    36                 break;
    37             }
    38         }
    39 }
    40 int main(){
    41     cin>>n;
    42     for(ll i = 1;i <= n;i++)scanf("%d%d",&x[i],&y[i]);
    43     for(ll i = 1;i <= n;i++)father[i] = i;
    44     for(ll i = 1;i <= n;i++)
    45         for(ll j = i+1;j <= n;j++){
    46             cnt++;
    47             e[cnt].x = i;
    48             e[cnt].y = j;
    49             e[cnt].w = dist(i,j);
    50         }
    51     Kruscal();
    52     return 0;
    53 }

    法二:Floyd

     1 /*
     2 problem:yibentong1000
     3 date:2019/5/11
     4 author:Lonely.Devil
     5 */
     6 
     7 #include<iostream>
     8 #include<cstdio>
     9 #include<algorithm>
    10 using namespace std;
    11 #define ll long long
    12 const ll maxn = 5e1+5;
    13 struct point{
    14     ll x,y;
    15 }p[maxn];
    16 ll map[maxn][maxn];
    17 ll n,ans;
    18 inline ll Abs(ll x){
    19     if(x < 0)x = -x;
    20     return x;
    21 }
    22 inline ll Min(ll x,ll y){
    23     return x < y ? x : y;
    24 }
    25 inline ll Max(ll x,ll y){
    26     return x > y ? x : y;
    27 }
    28 inline ll dist(int i,int j){
    29     return (Abs(p[i].x-p[j].x)+Abs(p[i].y-p[j].y)+1)/2;
    30 }
    31 inline void Floyd(){
    32     for(ll k = 1;k <= n;k++)
    33         for(ll i = 1;i <= n;i++)
    34             for(ll j = 1;j <= n;j++)
    35                 map[i][j] = min(map[i][j],max(map[k][j],map[i][k]));
    36 }
    37 int main(){
    38     cin>>n;
    39     for(ll i = 1;i <= n;i++)scanf("%lld%lld",&p[i].x,&p[i].y);
    40     for(ll i = 1;i <= n;i++)
    41         for(ll j = 1;j <= n;j++)
    42             if(i == j)map[i][j] = 0;
    43     for(ll i = 1;i <= n;i++)
    44         for(ll j = i+1;j <= n;j++)
    45             map[i][j] = map[j][i] = dist(i,j);
    46     Floyd();
    47     for(ll i = 1;i <= n;i++)
    48         for(ll j = i+1;j <= n;j++)
    49             if(ans < map[i][j])
    50                 ans = map[i][j];
    51     cout<<ans<<endl;
    52     return 0;
    53 }
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  • 原文地址:https://www.cnblogs.com/wangyifan124/p/10746540.html
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