zoukankan      html  css  js  c++  java
  • HDOJ/HDU 1328 IBM Minus One(水题一个,试试手)

    Problem Description
    You may have heard of the book ‘2001 - A Space Odyssey’ by Arthur C. Clarke, or the film of the same name by Stanley Kubrick. In it a spaceship is sent from Earth to Saturn. The crew is put into stasis for the long flight, only two men are awake, and the ship is controlled by the intelligent computer HAL. But during the flight HAL is acting more and more strangely, and even starts to kill the crew on board. We don’t tell you how the story ends, in case you want to read the book for yourself :-)

    After the movie was released and became very popular, there was some discussion as to what the name ‘HAL’ actually meant. Some thought that it might be an abbreviation for ‘Heuristic ALgorithm’. But the most popular explanation is the following: if you replace every letter in the word HAL by its successor in the alphabet, you get … IBM.

    Perhaps there are even more acronyms related in this strange way! You are to write a program that may help to find this out.

    Input
    The input starts with the integer n on a line by itself - this is the number of strings to follow. The following n lines each contain one string of at most 50 upper-case letters.

    Output
    For each string in the input, first output the number of the string, as shown in the sample output. The print the string start is derived from the input string by replacing every time by the following letter in the alphabet, and replacing ‘Z’ by ‘A’.

    Print a blank line after each test case.

    Sample Input
    2
    HAL
    SWERC

    Sample Output
    String #1
    IBM

    String #2
    TXFSD

    题意就是:输入一个大写的字符串,输出每一个大写字母后的一个大写字母。
    如果遇到Z就输出A。
    注意每一个测试后都有一个空行。

    水题一个!

    import java.util.Scanner;
    
    public class Main{
    
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            int t =sc.nextInt();
            int ti=0;
            while(t-->0){
                String str = sc.next();
                System.out.println("String #"+(++ti));
                for(int i=0;i<str.length();i++){
                    if(str.charAt(i)=='Z'){
                        System.out.print("A");
                    }else{
                        System.out.print((char)(str.charAt(i)+1));
                    }
                }
                System.out.println();
                System.out.println();
            }
        }
    }
    
  • 相关阅读:
    目前最大的IPV6安全风险有哪些?
    PHP中exec、system等函数调用linux命令问题
    ubuntu下LAMP环境安装
    Ubuntu配置Apache虚拟主机
    XML和YAML的区别与使用方法
    使用CURL访问站点的时候出现403的解决办法
    IPv6安装及使用手册
    SuperSlide2.1-滚动
    HTML常用手册
    关于Ajax参数的思考
  • 原文地址:https://www.cnblogs.com/webmen/p/5739147.html
Copyright © 2011-2022 走看看