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  • HDU5418.Victor and World(状压DP)

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    
    using namespace std;
    
    typedef long long ll;
    const int INF = 0x5f5f5f5f;
    const int MAX = 1 << 17;
    
    int mp[20][20];
    int dp[MAX + 1][20];    // dp[s][v] 走过s点,现在在v点 dp[S][0]
    
    int bit[1<<17];
    
    int main()
    {
        //freopen("in.txt", "r", stdin);
    
    	for(int i = 0; i<(1<<16); i++) // bit[i] := i的二进制有多少个1
        {
            bit[i] = 0;
            for (int j = 0; j <= 16; j++)
                if (i & (1 << j))
                  bit[i]++;
        }
    
        int t;
        int m, n;
        scanf("%d", &t);
        while (t--) {
            memset(mp, -1, sizeof mp);
            for (int i = 0; i < MAX; ++i)
                for (int j = 0; j < 16; ++j)
                    dp[i][j] = INF;
    
            scanf("%d%d", &n, &m);
            int a, b, c;
            for (int i = 0; i < m; ++i) {
                scanf("%d%d%d", &a, &b, &c);
                if (mp[a - 1][b - 1] == -1 || mp[a - 1][b - 1] > c)
                    mp[a - 1][b - 1] = mp[b - 1][a - 1] = c;
            }
    
            int maxn =  (1 << n) - 1;
    
    		dp[1][0] = 0;
            for (int s = 1; s <= maxn; ++s) {
    			for(int k = 0; k <= bit[s]; ++k) {
    				for (int v = 0; v < n; ++v) {
    					if (dp[s][v] != INF) {
    						for (int u = 0; u < n; ++u) {
    							if (mp[u][v] != -1) {
    								if (dp[s | (1 << u)][u] > dp[s][v] + mp[u][v])
    									dp[s | (1 << u)][u] = dp[s][v] + mp[u][v];
    							}
    						}
    					}
    				}
                }
            }
    
            printf("%d
    ", dp[maxn][0]);
        }
    
        return 0;
    }
    
    /**
    Input:
    2
    3 2
    1 2 2
    1 3 3
    5 4
    1 2 1
    2 3 1
    3 4 1
    4 5 1
    
    Output:
    10
    8
    */
    

      

    wa了好久,我只想知道

    for(int k = 0; k <= bit[s]; ++k) 

    什么意思,为什么要加这句?

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  • 原文地址:https://www.cnblogs.com/wenruo/p/4752229.html
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