zoukankan      html  css  js  c++  java
  • 1508. Range Sum of Sorted Subarray Sums

    Given the array nums consisting of n positive integers. You computed the sum of all non-empty continous subarrays from the array and then sort them in non-decreasing order, creating a new array of n * (n + 1) / 2 numbers.

    Return the sum of the numbers from index left to index right (indexed from 1), inclusive, in the new array. Since the answer can be a huge number return it modulo 10^9 + 7.

    Example 1:

    Input: nums = [1,2,3,4], n = 4, left = 1, right = 5
    Output: 13 
    Explanation: All subarray sums are 1, 3, 6, 10, 2, 5, 9, 3, 7, 4. After sorting them in non-decreasing order we have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 1 to ri = 5 is 1 + 2 + 3 + 3 + 4 = 13. 
    

    Example 2:

    Input: nums = [1,2,3,4], n = 4, left = 3, right = 4
    Output: 6
    Explanation: The given array is the same as example 1. We have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 3 to ri = 4 is 3 + 3 = 6.
    

    Example 3:

    Input: nums = [1,2,3,4], n = 4, left = 1, right = 10
    Output: 50
    

    Constraints:

    • 1 <= nums.length <= 10^3
    • nums.length == n
    • 1 <= nums[i] <= 100
    • 1 <= left <= right <= n * (n + 1) / 2
    
    
    class Solution {
        public int rangeSum(int[] nums, int n, int left, int right) {
            List<Integer> list = new ArrayList();
            list.add(0);
            for(int i = 0; i < n; i++){
                int cur = nums[i];
                list.add(cur);
                for(int j = i+1; j < n; j++){                
                    cur += nums[j];
                    list.add(cur);
                }            
            }
            Collections.sort(list);
            //return list.size();
            int sum = 0;
            for(int i = left; i <= right; i++){
                sum += list.get(i);
                sum %= 1000000007;
            }
            return sum;
        }
    }
    
    
    
     

    continuous array

  • 相关阅读:
    转载-WebSocket协议解析
    django sqlite3数据迁入postgresql
    使用JenKins实现自动执行python脚本
    调用函数的局部变量
    打开新窗口获取元素
    邮箱登录脚本
    购物车小程序
    循环
    格式化的输出
    使用#号输出图形,可以指定宽和高
  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/13287055.html
Copyright © 2011-2022 走看看