zoukankan      html  css  js  c++  java
  • 1350. Primary Arithmetic

    Children are taught to add multi-digit numbers from right-to-left one digit at a time.  Many find the "carry" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge.  Your job is to count the number of  carry operations for each of a set of addition problems so that educators may assess their difficulty.

    Each line of input contains two unsigned integers less than 10 digits.   The last line of input contains 0 0.  For each line of input except the  last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.

    Sample Input

    123 456
    555 555
    123 594
    0 0
    

    Output for Sample Input

    No carry operation.
    3 carry operations.
    1 carry operation.
    
    #include<iostream>
    #include<cmath>
    using namespace std;
    int main()
    {
        unsigned int m,n,sum,i;
        //cin>>m>>n;
        while(cin>>m>>n)
        {
            if(m==0&&n==0)
              break;
            unsigned int temp;
            if(m<n)
            {
                temp=m;
                m=n;
                n=temp;
            }        
            unsigned int m1,n1;
            i=0;
            sum=0;
        while(m>0)
            {
            m1=m%10;
            n1=n%10;
            if(m1+n1+i>=10)
            {
                i=1;
                sum++;
            }
            else {
                i=0;
            }
            m=m/10;
            n=n/10;
            
        }
        while(n>0)
        {
            if(n%10+i>=10)
            {
                i=1;
                sum++;
            }
            else
            {
                i=0;
            }
            n=n/10;
        }
        if(sum==0)
        {
           cout<<"No carry operation."<<endl;
        }  
        else if(sum==1)
        {
           cout<<sum<<" carry operation."<<endl;
        }  
        else if(sum>1)
        {
           cout<<sum<<" carry operations."<<endl;
        }
            //cin>>m>>n; 
        }
            return 0;
    }
    View Code
  • 相关阅读:
    web前端【第十四篇】Bootstrap简单使用
    web前端【第十三篇】jQuery扩展和事件
    web前端【第十二篇】jQuery文档相关操作
    web前端【第十一篇】jQuery属性相关操作
    页面组件
    索引
    前端基础
    pymysql与mysql各功能
    mysql数据操作
    mysql表相关操作
  • 原文地址:https://www.cnblogs.com/wft1990/p/6057589.html
Copyright © 2011-2022 走看看