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  • 18. 4Sum

    1. 问题描述

    Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target.

    Note: The solution set must not contain duplicate quadruplets.

    For example, given array S = [1, 0, -1, 0, -2, 2], and target = 0.
    
    A solution set is:
    [
        [-1, 0, 0, 1],
        [-2, -1, 1, 2],
        [-2, 0, 0, 2]
    ]

    Tags:Array Hash Table Two Pointers

    Similar Problems: (E) Two Sum (M) 3Sum

    2. 解答思路

    3. 代码

     1 #include <vector>
     2 #include <map>
     3 #include <algorithm>
     4 #include <string>
     5 using namespace std;
     6 class Solution {
     7 public:
     8     vector<vector<int>> fourSum(vector<int>& nums, int target) {
     9         vector<vector<int>> vResult;
    10         if (!Validate(nums))
    11         {
    12             return vResult;
    13         }
    14         std::map<std::string, bool> isExist;//用于存储已存在的四元组
    15         int vSize = nums.size();
    16         std::sort(nums.begin(), nums.end());
    17         int Fir, Sec, Trd, Fou;
    18         for (Fir=0; Fir<=vSize-4; Fir++)
    19         {
    20             int t1 = target - nums[Fir];
    21             for (Sec=Fir+1; Sec<=vSize-3; Sec++)
    22             {
    23                 int t = t1 - nums[Sec];
    24                 for (Trd=Sec+1, Fou=vSize-1; Trd<Fou;)
    25                 {
    26                     int sum = nums[Trd] + nums[Fou];
    27                     if (sum < t)
    28                     {
    29                         Trd++;
    30                     }
    31                     else if (sum > t)
    32                     {
    33                         Fou--;
    34                     }
    35                     else
    36                     {
    37                         std::vector<int> vTemp;
    38                         vTemp.push_back(nums[Fir]);
    39                         vTemp.push_back(nums[Sec]);
    40                         vTemp.push_back(nums[Trd]);
    41                         vTemp.push_back(nums[Fou]);
    42                         
    43                         char pBuf[100];
    44                         sprintf(pBuf, "%d_%d_%d_%d", nums[Fir], nums[Sec], nums[Trd], nums[Fou]);
    45                         std::string str(pBuf);                        
    46                         if (0 == isExist.count(str))
    47                         {
    48                             isExist.insert(std::make_pair(str, true));
    49                             vResult.push_back(vTemp);
    50                         }
    51                         
    52                         Trd++;
    53                     }
    54                 }
    55             }
    56         }
    57         return vResult;
    58     }
    59 private:
    60     bool Validate(vector<int>& nums)
    61     {
    62         if (nums.size() < 4)
    63         {
    64             return false;
    65         }
    66         return true;
    67     }
    68 };

    4. 反思

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  • 原文地址:https://www.cnblogs.com/whl2012/p/5578845.html
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