zoukankan      html  css  js  c++  java
  • (简单) UVA 11624 Fire! ,BFS。

      Description

      Joe works in a maze. Unfortunately, portions of the maze have caught on fire, and the owner of the maze neglected to create a fire escape plan. Help Joe escape the maze.

      Given Joe's location in the maze and which squares of the maze are on fire, you must determine whether Joe can exit the maze before the fire reaches him, and how fast he can do it.

      Joe and the fire each move one square per minute, vertically or horizontally (not diagonally). The fire spreads all four directions from each square that is on fire. Joe may exit the maze from any square that borders the edge of the maze. Neither Joe nor the fire may enter a square that is occupied by a wall.

      题目就是迷宫问题,然后加了火,不过这个题被坑了,原来火不只是一个,可以有很多个。。。

      这个题先从火BFS一遍,这样就可以知道火多长时间后烧到某一块,然后从人BFS,当走到这时火已经烧过来的话就算不能通过就好了。

    代码如下:

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<queue>
    #include<cmath>
    
    using namespace std;
    
    bool map1[1005][1005];
    int rem[1005][1005];
    int Frem[1005][1005];
    int N,M;
    int Si,Sj,Fi[1000006],Fj[1000006];
    int cou;
    
    bool judge(int x,int y,int temp)
    {
        if(x<=0||y<=0||x>N||y>M)
            return 0;
    
        if(!map1[x][y])
            return 0;
        
        if(rem[x][y])
            return 0;
    
        if(Frem[x][y]>-1&&temp>=Frem[x][y])
            return 0;
    
        return 1;
    }
    
    bool judge1(int x,int y)
    {
        if(x<=0||y<=0||x>N||y>M)
            return 0;
    
        if(!map1[x][y])
            return 0;
    
        if(Frem[x][y]!=-1)
            return 0;
    
        return 1;
    }
    
    int slove()
    {
        queue <int> que;
        int temp,t1,t2;
    
        que.push(Si*1010+Sj);
        rem[Si][Sj]=1;
    
        while(!que.empty())
        {
            temp=que.front();
            que.pop();
    
            t1=temp/1010;
            t2=temp%1010;
            temp=rem[t1][t2];
    
            if(t1==1||t2==1||t1==N||t2==M)
                return temp;
    
            --t1;
            if(judge(t1,t2,temp))
            {
                que.push(t1*1010+t2);
                rem[t1][t2]=temp+1;
            }
            t1+=2;
            if(judge(t1,t2,temp))
            {
                que.push(t1*1010+t2);
                rem[t1][t2]=temp+1;
            }
            --t1;
            --t2;
            if(judge(t1,t2,temp))
            {
                que.push(t1*1010+t2);
                rem[t1][t2]=temp+1;
            }
            t2+=2;
            if(judge(t1,t2,temp))
            {
                que.push(t1*1010+t2);
                rem[t1][t2]=temp+1;
            }
        }
    
        return -1;
    }
    
    void init()
    {
        queue <int> que;
        int temp,t1,t2;
        for(int i=0;i<cou;++i)
        {
            que.push(Fi[i]*1010+Fj[i]);
            Frem[Fi[i]][Fj[i]]=0;
        }
    
        while(!que.empty())
        {
            temp=que.front();
            que.pop();
    
            t1=temp/1010;
            t2=temp%1010;
            temp=Frem[t1][t2];
    
            --t1;
            if(judge1(t1,t2))
            {
                que.push(t1*1010+t2);
                Frem[t1][t2]=temp+1;
            }
            t1+=2;
            if(judge1(t1,t2))
            {
                que.push(t1*1010+t2);
                Frem[t1][t2]=temp+1;
            }
            --t1;
            --t2;    
            if(judge1(t1,t2))
            {
                que.push(t1*1010+t2);
                Frem[t1][t2]=temp+1;
            }
            t2+=2;
            if(judge1(t1,t2))
            {
                que.push(t1*1010+t2);
                Frem[t1][t2]=temp+1;
            }
        }
    }
    
    int main()
    {
        ios::sync_with_stdio(false);
    
        int T;
        int ans;
        char c;
        cin>>T;
    
        while(T--)
        {
            cou=0;
            cin>>N>>M;
            for(int i=1;i<=N;++i)
                for(int j=1;j<=M;++j)
                {
                    rem[i][j]=0;
                    Frem[i][j]=-1;
                    cin>>c;
                    if(c=='#'||c=='F')
                        map1[i][j]=0;
                    else
                        map1[i][j]=1;
    
                    if(c=='J')
                        Si=i,Sj=j;
                    if(c=='F')
                    {
                        Fi[cou]=i;
                        Fj[cou++]=j;
                    }
                }
    
            init();
    
            ans=slove();
    
            if(ans==-1)
                cout<<"IMPOSSIBLE
    ";
            else
                cout<<ans<<endl;
        }
    
        return 0;
    }
    View Code
  • 相关阅读:
    vault验证导出领域对象导入新的shecma是否生效
    开启vault下如何使用expdp
    vault创建领域不让sys/system访问,但是可以让其他用户访问
    vault应用例子(禁止sys用户访问其他用户下的表)
    11g关闭vault
    11g配置vault
    11g单节点配置em
    vue中 js获取图片尺寸 设置不同样式
    vue 模块化 路由拆分配置
    vue 弹窗时 监听手机返回键关闭弹窗(页面不跳转)
  • 原文地址:https://www.cnblogs.com/whywhy/p/4229921.html
Copyright © 2011-2022 走看看