Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
Follow up:
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
Code:
class Solution {
public:
void setZeroes(vector<vector<int> > &matrix) {
int m=matrix.size();
int n=matrix[0].size();
int firstrow=0;
int firstcol=0;
for(int i=0;i<n;i++)
if(matrix[0][i]==0){
firstrow=1;
break;
}
for(int j=0;j<m;j++)
if(matrix[j][0]==0){
firstcol=1;
break;
}
for(int j=0;j<m;j++)
for(int i=0;i<n;i++){
if(matrix[j][i]==0){
matrix[j][0]=0;
matrix[0][i]=0;
}
}
for(int i=1;i<n;i++)
if(matrix[0][i]==0)
for(int j=1;j<m;j++)
matrix[j][i]=0;
for(int j=1;j<m;j++)
if(matrix[j][0]==0)
for(int i=1;i<n;i++)
matrix[j][i]=0;
if(firstrow==1)
for(int i=0;i<n;i++)
matrix[0][i]=0;
if(firstcol==1)
for(int j=1;j<m;j++)
matrix[j][0]=0;
}
};