https://atcoder.jp/contests/abc142/tasks/abc142_d
题意
求满足互素条件下的A和B的因子最多有几个
思路:
分解gcd(A,B)的质因子,再加上1;
#include <iostream> #include<algorithm> #include<string> using namespace std; const int maxn =1e5+10; long long gcd(long long x,long long y) { if(y==0)return x; return gcd(y,x%y); } int main() { long long x,y; cin >> x >> y; long long g=gcd(x,y); long long ans=0; for(long long i=2;i<= g / i; i++) { if(g%i==0) { ans++; while(g%i==0) g/=i; } } if(g>1) ans++; cout << ans +1 <<endl; return 0; }