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  • Game!

    Description
    One day, zbybr is playing a game with blankcqk, here are the rules of the game:
    There is a circle of N stones, zbybr and blankcqk take turns taking the stones.
    Each time, one player can choose to take one stone or take two adjacent stones
    You should notice that if there are 4 stones, and zbybr takes the 2nd, the 1st and 3rd stones are still not adjacent.
    The winner is the one who takes the last stone.
    Now, the game begins and zbybr moves first.
    If both of them will play with the best strategy, can you tell me who will win the game?
    Input
    The first line of input contains an integer T, indicating the number of test cases (T≈100000).

    For each case, there is a positive integer N (N ≤ 10^18).

    Output
    Output the name of the winner.

    Sample Input
    2
    1
    2
    Sample Output
    zbybr
    zbybr

    解题思路:

    这也是一道博弈类型的题,可以拿走一块或者两块石头,zbybr先手,利用对称局势
    #include <stdio.h>
    int main()
    {
        int t;
        long long n;
        scanf("%d",&t);
        while(t--)
        {
            scanf("%lld",&n);
            if(n>=3)
                printf("blankcqk
    ");
            else
                printf("zbybr
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/wkfvawl/p/8666085.html
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