python实例5-表格打印

编写一个名为printTable()的函数，它接受字符串的列表的列表，将它显示在组织良好的表格中，每列右对齐。假定所有内层列表都包含同样数目的字符串。例如，该值可能看起来像这样： 

table_data = [['apples', 'oranges', 'cherries', 'banana'],
              ['Alice', 'Bob', 'Carol', 'David'],
              ['dogs', 'cats', 'moose', 'goose']]

你的 printTable()函数将打印出：

apples   Alice dogs
oranges  Bob   cats
cherries Carol moose
banana   David goose　　

示例代码1：

import copy


def count_width(the_list):
    new_list = copy.deepcopy(the_list)
    col_widths = [0]*len(the_list)
    i = 0
    while i < len(new_list):
        new_list[i].sort(key=lambda x: len(x), reverse=True)
        col_widths[i] = new_list[i][0]
        i = i+1
    return col_widths


def list_ljust(the_list):
    widths = count_width(the_list)
    for j in range(len(the_list[0])):
        for i in range(len(the_list)):
            print(the_list[i][j].ljust(len(widths[i])), end=' ')
        print('
')


table_data = [['apples', 'oranges', 'cherries', 'banana'],
              ['Alice', 'Bob', 'Carol', 'David'],
              ['dogs', 'cats', 'moose', 'goose']]
list_ljust(table_data)　　

sort方法：

lambda函数：

示例代码2：

def count_widths(the_list):
    col_widths = [0]*len(the_list)
    for i in range(len(the_list)):
        for j in range(len(the_list[0])):
            if len(the_list[i][j]) > max_len:
                max_len = len(the_list[i][j])
        col_widths[i] = max_len
    return col_widths


def list_ljust(the_list):
    widths = count_widths(the_list)
    print(widths)
    for j in range(len(the_list[0])):
        for i in range(len(the_list)):
            print(the_list[i][j].ljust(widths[i]), end=' ')
        print('
')


table_data = [['apples', 'oranges', 'cherries', 'banana'],
              ['Alice', 'Bob', 'Carol', 'David'],
              ['dogs', 'cats', 'moose', 'goose']]
list_ljust(table_data)