C语言实现简单一元二次方程的求解

#include<stdio.h>
#include<math.h>
int main()
{
    while(1)
    {
        double a,b,c;
        double delta;
        double x1,x2;
        char ch;
        printf("请输入三个系数：
");
        printf("a = ");
        scanf("%lf",&a);
        printf("b = ");
        scanf("%lf",&b);
        printf("c = ");
        scanf("%lf",&c);
        delta = b*b - 4*a*c;
        if(delta > 0)
        {
            printf("该方程有两个解：
");
            x1 = (-b + sqrt(delta))/(2.0*a);
            x2 = (-b - sqrt(delta))/(2.0*a);
            printf("x1 = %lf
",x1);
            printf("x2 = %lf
",x2);
        }
        else if(delta == 0)
        {
            printf("该方程有唯一解：
");
             x1 = (-b + sqrt(delta))/(2.0*a);
            x2=x1;
            printf("x1 = %lf
",x1);
            printf("x2 = %lf
",x2);
        }
        else
        {
            printf("该方程无解！
");
        }

        getchar();
        printf("是否继续下组计算：（Y/N）
");
        scanf("%c",&ch);
        if(ch == 'N')
            break;
    }
    return 0;
}