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  • POJ 2513 Colored Sticks 字典树、并查集、欧拉通路

    Description

    You are given a bunch of wooden sticks. Each endpoint of each stick is colored with some color. Is it possible to align the sticks in a straight line such that the colors of the endpoints that touch are of the same color?

    Input

    Input is a sequence of lines, each line contains two words, separated by spaces, giving the colors of the endpoints of one stick. A word is a sequence of lowercase letters no longer than 10 characters. There is no more than 250000 sticks.

    Output

    If the sticks can be aligned in the desired way, output a single line saying Possible, otherwise output Impossible.

    Sample Input

    blue red
    red violet
    cyan blue
    blue magenta
    magenta cyan
    

    Sample Output

    Possible



    #include <stdio.h>
    #include <iostream>
    using namespace std;
    
    int id = 0, par[500010], degree[500010] = {0};
    
    int find_set(int x)
    {
        return par[x] != x ? par[x] = find_set(par[x]) : x;
    }
    
    struct Trie_node
    {
        int flag, id;
        struct Trie_node *next[26];
        Trie_node()
        {
            for(int i = 0; i < 26; i++)
                next[i] = NULL;
            flag = 0;
        }
    };
    
    int trie_insert(struct Trie_node *p, char s[])
    {
        for(int i = 0; s[i]; i++)
        {
            if(p->next[s[i]-'a'] == NULL)
                p->next[s[i]-'a'] = new Trie_node;
            p = p->next[s[i]-'a'];
        }
        if(p->flag != 1)
        {
            p->flag = 1;
            p->id = ++id;
        }
        return p->id;
    }
    
    bool check()
    {
        int x = find_set(1);
        for(int i = 2; i <= id; i++)
        {
            if(find_set(i) != x)
                return 0;
        }
        int degree_odd = 0;
        for(int i = 1; i <= id; i++)
        {
            if(degree[i] & 1)
                degree_odd++;
        }
        return (degree_odd == 1 || degree_odd > 2) ? 0 : 1;
    }
    
    int main()
    {
        for(int i = 0; i <= 500000; i++)
            par[i] = i;
        struct Trie_node *root = new Trie_node;
        char s1[12], s2[12];
        while(scanf("%s %s", s1, s2) != EOF)
        {
            int x = trie_insert(root, s1);
            int y = trie_insert(root, s2);
            degree[x]++;
            degree[y]++;
            int fx = find_set(x);
            int fy = find_set(y);
            if(fx != fy)
                par[fx] = fy;
        }
        printf("%s
    ", check() ? "Possible" : "Impossible");
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/wolfred7464/p/3231730.html
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