确实有段时间没怎么写python,手写还不上机是真的难受。
而且break 跳出循环最内一层的事情都要想一下才能写得出来。
题目如下:
寻找一个字符串最大连续出现次数,并放入字典中,
s="aaccccababbbb"{'a': 2, 'b': 4, 'c': 4}
代码如下
s="aaccccvbbbbbbbbbdddddddddeeedeeeeettt" dict1={} ls=[i for i in s] for i in set(ls): dict1[i]=1 print(dict1) for i in range(len(ls)): count=1 for j in range(i+1,len(ls)): if ls[i]==ls[j]: count += 1 if dict1.get(ls[i]) <= count: dict1[ls[i]]=count else: pass else: break print(dict1) # # {'c': 5, 'e': 6, 'v': 2, 'b': 10, 'd': 10, 'a': 3, 't': 4} # {'c': 5, 'b': 10, 't': 4, 'a': 3, 'd': 10, 'v': 2, 'e': 6}
join 打错哦了
str=>list,set 可以直接list() set()方法转换
ls="aaccccvbbbbbbbbbdddddddddeeedeeeeettt" dict1={} for i in set(ls): dict1[i]=1 print(dict1) for i in range(len(ls)): count = 1 for j in range(i+1,len(ls)): if ls[i] == ls[j]: count += 1 if dict1.get(ls[i]) <= count: dict1[ls[i]]=count else: break print(dict1)