php curl伪造referer

 

CURL方式：

 

 

$ch = curl_init();  
   
curl_setopt ($ch, CURLOPT_URL, "http://www.yyyy.com");  
   
curl_setopt ($ch, CURLOPT_REFERER, "http://www.xxxx.com/");  
   
curl_exec ($ch);  
   
curl_close ($ch);  

 

 

 

SOCKET方式：

 

 

  

$server = 'www.yyyy.com';  
   
$host = 'www.yyyy.com';  
   
$target = 'index.php';  
   
$referer = 'http://www.xxxx.com/'; // Referer  
   
$port = 80;  
   
$fp = fsockopen($server, $port, $errno, $errstr, 30);  
   
if (!$fp){  
   
  echo "$errstr ($errno)
";  
   
}else{  
   
$out = "GET $target HTTP/1.1
";  
   
$out .= "Host: $host
";  
   
$out .= "Referer: $referer
";  
   
$out .= "Connection: Close

";  
   
fwrite($fp, $out);  
   
while (!feof($fp)){  
   
echo fgets($fp, 128);  
   
}  
   
fclose($fp);  
   
}  

file_get_contents方法：

 

 

$opt=array('http'=>array('header'=>"Referer: $refer"));   
   
$context=stream_context_create($opt);   
   
$file_contents = file_get_contents($url,false, $context);  

通过上面的代码，我们就把referer地址伪装为http://www.xxxx.com，你可以写一段代码：

$_SERVER['HTTP_REFERER'];

查看到这个referer地址，就是这么简单，所以referer也不是什么可靠的数据了