Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
一个链表删除给定的元素。
public ListNode removeElements(ListNode head, int val) {
ListNode curr = head;
while(head != null && head.val == val) head = head.next; //先判断头节点值是不是val
while(curr != null && curr.next != null)
{
if(curr.next.val == val)
curr.next = curr.next.next; //删除节点
else
curr = curr.next;
}
return head;
}
还可以使用递归方法,代码非常的简介
public ListNode removeElements(ListNode head, int val) {
if(head == null) return null;
head.next = removeElements(head.next,val);
return head.val == val ? head.next : head;
}