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  • 子查询

    /*

    含义:
    出现在其他语句中的select语句,称为子查询或内查询
    外部的查询语句,称为主查询或外查询
    分类:
    按子查询出现的位置:
      select后面:
          仅仅支持标量子查询

      from后面:
          支持表子查询

      where或having后面:★
          标量子查询(单行) √
          列子查询 (多行) √
      
          行子查询

      exists后面(相关子查询)
          表子查询

    按结果集的行列数不同:
      标量子查询(结果集只有一行一列)
      列子查询(结果集只有一列多行)
      行子查询(结果集有一行多列)
      表子查询(结果集一般为多行多列)
    */

    #一、where或having后面
    /*
    1、标量子查询(单行子查询)
    2、列子查询(多行子查询)
    3、行子查询(多列多行)
    特点:
    ①子查询放在小括号内
    ②子查询一般放在条件的右侧
    ③标量子查询,一般搭配着单行操作符使用
    > < >= <= = <>
    列子查询,一般搭配着多行操作符使用
    in、any/some、all
    ④子查询的执行优先于主查询执行,主查询的条件用到了子查询的结果
    */

    #1.标量子查询★
    #案例1:谁的工资比 Abel 高?
    #①查询Abel的工资

    SELECT salary
    FROM employees
    WHERE last_name = 'Abel';


    #②查询员工的信息,满足 salary>①结果

    SELECT *
    FROM employees
    WHERE salary>(
    SELECT salary
    FROM employees
    WHERE last_name = 'Abel'
    );


    #案例2:返回job_id与141号员工相同,salary比143号员工多的员工 姓名,job_id 和工资
    #①查询141号员工的job_id

    SELECT job_id
    FROM employees
    WHERE employee_id = 141;


    #②查询143号员工的salary

    SELECT salary
    FROM employees
    WHERE employee_id = 143;


    #③查询员工的姓名,job_id 和工资,要求job_id=①并且salary>②

    SELECT last_name,job_id,salary
    FROM employees
    WHERE job_id = (
    SELECT job_id
    FROM employees
    WHERE employee_id = 141
    ) AND salary>(
    SELECT salary
    FROM employees
    WHERE employee_id = 143
    );


    #案例3:返回公司工资最少的员工的last_name,job_id和salary
    #①查询公司的 最低工资

    SELECT MIN(salary)
    FROM employees;


    #②查询last_name,job_id和salary,要求salary=①

    SELECT last_name,job_id,salary
    FROM employees
    WHERE salary=(
    SELECT MIN(salary)
    FROM employees
    );


    #案例4:查询最低工资大于50号部门最低工资的部门id和其最低工资
    #①查询50号部门的最低工资

    SELECT MIN(salary)
    FROM employees
    WHERE department_id = 50;


    #②查询每个部门的最低工资

    SELECT MIN(salary),department_id
    FROM employees
    GROUP BY department_id;


    #③ 在②基础上筛选,满足min(salary)>①

    SELECT MIN(salary),department_id
    FROM employees
    GROUP BY department_id
    HAVING MIN(salary)>(
    SELECT MIN(salary)
    FROM employees
    WHERE department_id = 50
    );


    #非法使用标量子查询

    SELECT MIN(salary),department_id
    FROM employees
    GROUP BY department_id
    HAVING MIN(salary)>(
    SELECT salary
    FROM employees
    WHERE department_id = 250
    );


    #2.列子查询(多行子查询)★
    操作符 含义
    IN/NOT IN 等于列表中的任意一个
    ANY|SOME 和子查询返回的某一个值比较
    ALL 和子查询返回的所有值比较

    #案例1:返回location_id是1400或1700的部门中的所有员工姓名
    #①查询location_id是1400或1700的部门编号

    SELECT DISTINCT department_id
    FROM departments
    WHERE location_id IN(1400,1700);


    #②查询员工姓名,要求部门号是①列表中的某一个

    SELECT last_name
    FROM employees
    WHERE department_id <>ALL(
    SELECT DISTINCT department_id
    FROM departments
    WHERE location_id IN(1400,1700)
    );


    #案例2:返回其它工种中比job_id为‘IT_PROG’工种任一工资低的员工的员工号、姓名、job_id 以及salary
    #①查询job_id为‘IT_PROG’部门任一工资

    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG';


    #②查询员工号、姓名、job_id 以及salary,salary<(①)的任意一个

    SELECT last_name,employee_id,job_id,salary
    FROM employees
    WHERE salary<ANY(
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'
    ) AND job_id<>'IT_PROG';
    #或
    SELECT last_name,employee_id,job_id,salary
    FROM employees
    WHERE salary<(
    SELECT MAX(salary)
    FROM employees
    WHERE job_id = 'IT_PROG'
    ) AND job_id<>'IT_PROG';


    #案例3:返回其它部门中比job_id为‘IT_PROG’部门所有工资都低的员工 的员工号、姓名、job_id 以及salary

    SELECT last_name,employee_id,job_id,salary
    FROM employees
    WHERE salary<ALL(
    SELECT DISTINCT salary
    FROM employees
    WHERE job_id = 'IT_PROG'
    ) AND job_id<>'IT_PROG';
    #或
    SELECT last_name,employee_id,job_id,salary
    FROM employees
    WHERE salary<(
    SELECT MIN( salary)
    FROM employees
    WHERE job_id = 'IT_PROG'
    ) AND job_id<>'IT_PROG';


    #3、行子查询(结果集一行多列或多行多列)

    #案例:查询员工编号最小并且工资最高的员工信息

    SELECT *
    FROM employees
    WHERE (employee_id,salary)=(
    SELECT MIN(employee_id),MAX(salary)
    FROM employees
    );
    #①查询最小的员工编号
    SELECT MIN(employee_id)
    FROM employees;
    
    
    #②查询最高工资
    SELECT MAX(salary)
    FROM employees
    
    
    #③查询员工信息
    SELECT *
    FROM employees
    WHERE employee_id=(
    SELECT MIN(employee_id)
    FROM employees
    )AND salary=(
    SELECT MAX(salary)
    FROM employees
    );

    #二、select后面
    /*
    仅仅支持标量子查询
    */
    #案例:查询每个部门的员工个数

    SELECT d.*,(
    SELECT COUNT(*)
    FROM employees e
    WHERE e.department_id = d.`department_id`
    ) 个数
    FROM departments d;

    #案例2:查询员工号=102的部门名、

    SELECT (
    SELECT department_name
    FROM departments d
    INNER JOIN employees e
    ON d.department_id=e.department_id
    WHERE e.employee_id=102
    ) 部门名;
    
    
    ---错---
    SELECT (
    SELECT department_name,e.department_id
    FROM departments d
    INNER JOIN employees e
    ON d.department_id=e.department_id
    WHERE e.employee_id=102
    ) 部门名;


    #三、from后面
    /*
    将子查询结果充当一张表,要求必须起别名
    */

    #案例:查询每个部门的平均工资的工资等级
    #①查询每个部门的平均工资

    SELECT AVG(salary),department_id
    FROM employees
    GROUP BY department_id
    SELECT * FROM job_grades;


    #②连接①的结果集和job_grades表,筛选条件平均工资 between lowest_sal and highest_sal

    SELECT ag_dep.*,g.`grade_level`
    FROM (
    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id
    ) ag_dep
    INNER JOIN job_grades g
    ON ag_dep.ag BETWEEN lowest_sal AND highest_sal;


    #四、exists后面(相关子查询)
    /*
    语法:
    exists(完整的查询语句)
    结果:
    1或0

    */

    SELECT EXISTS(SELECT employee_id FROM employees WHERE salary=300000);


    #案例1:查询有员工的部门名

    #in
    SELECT department_name
    FROM departments d
    WHERE d.`department_id` IN(
    SELECT department_id
    FROM employees
    )
    
    
    #exists
    SELECT department_name
    FROM departments d
    WHERE EXISTS(
    SELECT *
    FROM employees e
    WHERE d.`department_id`=e.`department_id`
    );

    #案例2:查询没有女朋友的男神信息

    #in
    SELECT bo.*
    FROM boys bo
    WHERE bo.id NOT IN(
    SELECT boyfriend_id
    FROM beauty
    )
    
    
    #exists
    SELECT bo.*
    FROM boys bo
    WHERE NOT EXISTS(
    SELECT boyfriend_id
    FROM beauty b
    WHERE bo.`id`=b.`boyfriend_id`
    );
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  • 原文地址:https://www.cnblogs.com/wzhqzm/p/13336797.html
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