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  • 633. Sum of Square Numbers

    Given a non-negative integer c, your task is to decide whether there're two integers a and b such that a2 + b2 = c.

    Example 1:

    Input: 5
    Output: True
    Explanation: 1 * 1 + 2 * 2 = 5
    

    Example 2:

    Input: 3
    Output: False
    题目含义:给一个数字c,判断是否满足a平方+b平方=c
    思路:a和b最大为c开根号,最小为0.
     1     public boolean judgeSquareSum(int c) {
     2         int a=0;
     3         int b=(int)Math.sqrt(c);
     4         while (a<=b)
     5         {
     6             double sum = a*a + b*b;
     7             if (sum ==c) return true;
     8             if (sum<c) a++;
     9             else b--;
    10         }
    11         return false;        
    12     }
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  • 原文地址:https://www.cnblogs.com/wzj4858/p/7701654.html
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