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  • 94. Binary Tree Inorder Traversal

    Given a binary tree, return the inorder traversal of its nodes' values.

    For example:
    Given binary tree [1,null,2,3],

       1
        
         2
        /
       3
    

    return [1,3,2].

    题目含义:用中序遍历树并输出

     1     private void middleParserTree(TreeNode root,List<Integer> result)
     2     {
     3         if (root == null) return;
     4        
     5         middleParserTree(root.left,result);
     6         result.add(root.val);
     7         middleParserTree(root.right,result);
     8     }
     9     public List<Integer> inorderTraversal(TreeNode root) {
    10         List<Integer> result = new ArrayList<>();
    11         middleParserTree(root,result);
    12         return result;
    13     }
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  • 原文地址:https://www.cnblogs.com/wzj4858/p/7715651.html
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