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  • 234. Palindrome Linked List

    Given a singly linked list, determine if it is a palindrome.

    题目含义:给定一个单列表,判断是否构成回文

     1     public boolean isPalindrome(ListNode head) {
     2         Stack<Integer> valueStack = new Stack<>();
     3         if (head == null) return true;
     4         ListNode runer = head;
     5         ListNode walker = head;
     6         while (runer.next != null && runer.next.next != null)
     7         {
     8             valueStack.push(walker.val);
     9             runer = runer.next.next;
    10             walker = walker.next;
    11         }
    12         if (runer.next != null)
    13         {
    14 //            列表有偶数个节点
    15             if (walker.val != walker.next.val) return false;
    16             walker = walker.next.next;
    17         }else{
    18             walker = walker.next;
    19         }
    20         while (walker != null)
    21         {
    22             if (walker.val != valueStack.pop()) return false;
    23             walker = walker.next;
    24         }
    25         return true;
    26         
    27     }
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  • 原文地址:https://www.cnblogs.com/wzj4858/p/7724277.html
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