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  • HDU 1251 统计难题(字典树)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?

    pid=1251


    题意:先给出字典。每次查询一个单词,求以该单词为前缀的个数。


    思路:裸字典树


    代码

    #include <iostream>
    #include <stdio.h>
    #include <string.h>
    #include <math.h>
    #include <algorithm>
    #include <string>
    
    using namespace std;
    
    #define lson l, m, rt << 1
    #define rson m + 1, r, rt << 1 | 1
    #define ceil(x, y) (((x) + (y) - 1) / (y))
    
    const int SIZE = 30;
    const int N = 1e6 + 10;
    const int INF = 0x7f7f7f7f;
    
    struct Trie {
    	int val[SIZE];
    	int count;//以从根结点到当前结点的字符串为前缀的单词个数
    };
    
    int sz;
    Trie ch[N];
    
    int newnode() {
    	memset(ch[sz].val, 0, sizeof(ch[sz].val));
    	ch[sz].count = 0;
    	return sz++;
    }
    
    void insert(char *s) {
    	int u = 0;
    	for (int i = 0; s[i] != ''; i++) {
    		int idx = s[i] - 'a';
    		if (!ch[u].val[idx]) {
    			ch[u].val[idx] = newnode();
    		}
    		u = ch[u].val[idx];
    		ch[u].count++;
    	}
    }
    
    int findpre(char *s) {
    	int u = 0;
    	for (int i = 0; s[i] != ''; i++) {
    		int idx = s[i] - 'a';
    		if (!ch[u].val[idx])
    			return 0;
    		u = ch[u].val[idx];
    	}
    	return ch[u].count;
    }
    
    int main() {
    	char str[SIZE];
    	sz = 0;
    	newnode();
    	while (gets(str) && str[0]) {
    		insert(str);
    	}
    	while (scanf("%s", str) != EOF) {
    		printf("%d
    ", findpre(str));
    	}
    	return 0;
    }


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  • 原文地址:https://www.cnblogs.com/wzzkaifa/p/7169272.html
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