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  • 数据库中总结2

    单表查询
    单表查询的语法:

    SELECT 字段1,字段2... FROM 表名
    WHERE 条件
    GROUP BY field
    HAVING 筛选
    ORDER BY field
    LIMIT 限制条数

    关键字的执行优先级:

    from > where > group by > having > select > distinct > order by > limit

    简单查询

    create table employee(
      id int not null primary key auto_increment,
      name char(16) not null,
      sex enum('male','female') not null default 'male',
      age int(3) unsigned not null default 28,
      hire_date date not null,
      post char(50),
      post_comment char(100),
      salary double(15,2),
      office int,
      depart_id int	
    );
    
    insert into employee(name,sex,age,hire_date,post,salary,office,depart_id) values
    ('egon','male',18,'20170301','教导主任',7300.33,401,1), #以下是教学部
    ('alex','male',78,'20150302','teacher',1000000.31,401,1),
    ('wupeiqi','male',81,'20130305','teacher',8300,401,1),
    ('yuanhao','male',73,'20140701','teacher',3500,401,1),
    ('liwenzhou','male',28,'20121101','teacher',2100,401,1),
    ('jingliyang','female',18,'20110211','teacher',9000,401,1),
    ('jinxin','male',18,'19000301','teacher',30000,401,1),
    ('成龙','male',48,'20101111','teacher',10000,401,1),
    
    ('歪歪','female',48,'20150311','sale',3000.13,402,2),#以下是销售部门
    ('丫丫','female',38,'20101101','sale',2000.35,402,2),
    ('丁丁','female',18,'20110312','sale',1000.37,402,2),
    ('星星','female',18,'20160513','sale',3000.29,402,2),
    ('格格','female',28,'20170127','sale',4000.33,402,2),
    
    ('张野','male',28,'20160311','operation',10000.13,403,3), #以下是运营部门
    ('程咬金','male',18,'19970312','operation',20000,403,3),
    ('程咬银','female',18,'20130311','operation',19000,403,3),
    ('程咬铜','male',18,'20150411','operation',18000,403,3),
    ('程咬铁','female',18,'20140512','operation',17000,403,3)
    ;
    
    #简单查询
    select id,name,sex,age,hire_date,post,post_comment,salary,office,depart_id from employee;
    select name,salary from employee;
    
    #避免重复DISTINCT
    select distinct post FROM employee; 
    
    #通过四则运算查询
    SELECT name, salary*12 FROM employee;
    SELECT name, salary*12 AS Annual_salary FROM employee;
    SELECT name, salary*12 Annual_salary FROM employee;
    
    #定义显示格式
    CONCAT() 函数用于连接字符串
    SELECT CONCAT('姓名: ',name,' 年薪: ', salary*12) AS Annual_salary FROM employee;
    
    CONCAT_WS() 第一个参数为分隔符
    SELECT CONCAT_WS(':',name,salary*12) AS Annual_salary FROM employee;
    
    
    查出所有员工的名字,薪资,格式为<名字:egon>,<薪资:3000>
    select concat('<名字:',name,'> ','<薪资:',salary,'>') from employee;
    
    查出所有的岗位(去掉重复) 
    select distinct depart_id from employee;
    
    查出所有员工名字,以及他们的年薪,年薪的字段名为annual_year
    select name,salary*12 as annual_salary from employee;

    where 约束
    where字句中可以使用:

    比较运算符:><>= <= <> !=
    between 80 and 100 值在10到20之间
    in(80,90,100) 值是10或20或30
    like 'egon%'
    pattern可以是%或_,%表示任意多字符,_表示一个字符
    逻辑运算符:在多个条件直接可以使用逻辑运算符 and or not
    #1:单条件查询
    select name from employee where post='sale';
    
    #2:多条件查询
    select name,salary from employee where post='teacher' and salary>10000;
    
    #3:关键字BETWEEN AND
    select name,salary from employee 
    where salary BETWEEN 10000 AND 20000;
    
    select name,salary from employee 
    where salary NOT BETWEEN 10000 AND 20000;
    
    #4:关键字IS NULL(判断某个字段是否为NULL不能用等号,需要用IS)
    select name,post_comment from employee 
    where post_comment IS NULL;
    
    select name,post_comment from employee 
    where post_comment IS NOT NULL;
    
    select name,post_comment from employee 
    where post_comment=''; #注意''是空字符串,不是null
    
    #执行
    update employee set post_comment='' where id=2;
    select name,post_comment from employee where post_comment='';#有结果了
    
    #5:关键字IN集合查询
    select name,salary from employee 
      where salary=3000 OR salary=3500 OR salary=4000 OR salary=9000 ;
    
    select name,salary from employee 
      where salary in (3000,3500,4000,9000) ;
    
    select name,salary from employee 
      where salary not in (3000,3500,4000,9000) ;
    
    #6:关键字LIKE模糊查询
    通配符’%’
    select * from employee where name LIKE 'eg%';
    
    通配符’_’
    select * from employee where name LIKE 'al__';

    分组查询:group by
    分组指的是:将所有记录按照某个相同字段进行归类,比如针对员工信息表的职位分组,或者按照性别进行分组等

    小窍门:‘每’这个字后面的字段,就是我们分组的依据
    1.单独使用GROUP BY关键字分组
    SELECT post FROM employee GROUP BY post;
    2.GROUP BY关键字和GROUP_CONCAT()函数一起使用
    SELECT post,GROUP_CONCAT(name) FROM employee GROUP BY post;#按照岗位分组,并查看组内成员名
    SELECT post,GROUP_CONCAT(name) as emp_members FROM employee GROUP BY post;
    3.GROUP BY与聚合函数一起使用
    select post,count(id) as count from employee group by post;#按照岗位分组,并查看每个组有多少人	
    设置ONLY_FULL_GROUP_BY
    set global sql_mode='ONLY_FULL_GROUP_BY';
    quit #设置成功后,一定要退出,然后重新登录方可生效


    聚合函数
    聚合函数聚合的是组的内容,若是没有分组,则默认一组

    SELECT COUNT(*) FROM employee;
    SELECT COUNT(*) FROM employee WHERE depart_id=1;
    SELECT MAX(salary) FROM employee;
    SELECT MIN(salary) FROM employee;
    SELECT AVG(salary) FROM employee;
    SELECT SUM(salary) FROM employee;
    SELECT SUM(salary) FROM employee WHERE depart_id=3;


    having过滤

    执行优先级从高到低:where > group by > having 
    #1. Where 发生在分组group by之前,因而Where中可以有任意字段,但是绝对不能使用聚合函数。
    #2. Having发生在分组group by之后,因而Having中可以使用分组的字段,无法直接取到其他字段,可以使用聚合函数
    select @@global.sql_mode;
    select * from employee where salary > 100000;
    select * from employee having salary > 100000;#错误
    
    select post,group_concat(name) from employee group by post having salary > 10000;#错误,分组后无法直接取到salary字段
    select post,group_concat(name) from employee group by post having avg(salary) > 10000;

    查询排序:order by
    按单列排序

    SELECT * FROM employee ORDER BY salary;
    SELECT * FROM employee ORDER BY salary ASC;
    SELECT * FROM employee ORDER BY salary DESC; 

    按多列排序:先按照age排序,如果年纪相同,则按照薪资排序

    SELECT * from employee
    ORDER BY age,
    salary DESC;
    1. 查询所有员工信息,先按照age升序排序,如果age相同则按照hire_date降序排序
    select * from employee order by age asc,hire_date desc;
    2. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列	
    select post,avg(salary) from employee group by post 
    having avg(salary)>10000 order by avg(salary) desc;

    限制查询记录数

    SELECT * FROM employee ORDER BY salary DESC LIMIT 3; #默认初始位置为0
    
    SELECT * FROM employee ORDER BY salary DESC
    LIMIT 0,5; #从第0开始,即先查询出第一条,然后包含这一条在内往后查5条
    
    SELECT * FROM employee ORDER BY salary DESC
    LIMIT 5,5; #从第5开始,即先查询出第6条,然后包含这一条在内往后查5条

     

    使用正则表达式查询

    select * from employee where name REGEXP '^ale';
    
    select * from employee where name REGEXP 'on$';
    
    select * from employee where name REGEXP 'm{2}';
    
    查看所有员工中名字是jin开头,n或者g结果的员工信息
    select * from employee where name regexp '^jin.*[gn]$';
    

    多表连接查询
    准备表

    #建表
    create table department(
    id int,
    name varchar(20) 
    );
    
    create table employee(
    id int primary key auto_increment,
    name varchar(20),
    sex enum('male','female') not null default 'male',
    age int,
    dep_id int
    );
    
    #插入数据
    insert into department values
    (200,'技术'),
    (201,'人力资源'),
    (202,'销售'),
    (203,'运营');
    
    insert into employee(name,sex,age,dep_id) values
    ('egon','male',18,200),
    ('alex','female',48,201),
    ('wupeiqi','male',38,201),
    ('yuanhao','female',28,202),
    ('liwenzhou','male',18,200),
    ('jingliyang','female',18,204)
    ;
    
    查询表
    desc department;
    desc employee;
    select * from department;
    select * from employee;

    多表连接查询
    外链接语法

    select 字段列表
      from 表1 inner|left|right join 表2
        on 表1.字段 = 表2.字段;

    交叉连接:不适用任何匹配条件。生成笛卡尔积

    select * from employee,department;

    内连接:只连接匹配的行

    #找两张表共有的部分,相当于利用条件从笛卡尔积结果中筛选出了正确的结果
    select employee.id,employee.name,employee.age,employee.sex,department.name from employee,department 
    where employee.dep_id=department.id;
    
    select employee.id,employee.name,employee.age,employee.sex,department.name from employee 
    inner join department on employee.dep_id=department.id;

    外链接之左连接:优先显示左表全部记录

    #以左表为准,即找出所有员工信息,当然包括没有部门的员工
    select employee.id,employee.name,department.name as depart_name from employee 
    left join department on employee.dep_id=department.id;

    外链接之右连接:优先显示右表全部记录

    select employee.id,employee.name,department.name as depart_name from employee 
    right join department on employee.dep_id=department.id;  

    全外连接:显示左右两个表全部记录

    #注意:mysql不支持全外连接 full JOIN
    select * from employee 
    left join department on employee.dep_id = department.id
    union
    select * from employee 
    right join department on employee.dep_id = department.id
    ;
    #注意 union与union all的区别:union会去掉相同的纪录

    子查询

    #1:子查询是将一个查询语句嵌套在另一个查询语句中。
    #2:内层查询语句的查询结果,可以为外层查询语句提供查询条件。
    #3:子查询中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等关键字
    #4:还可以包含比较运算符:= 、 !=、> 、<等

    带IN关键字的子查询

    #查询平均年龄在25岁以上的部门名
    select id,name from department
    where id in 
    (select dep_id from employee group by dep_id having avg(age) > 25);
    
    #查看技术部员工姓名
    select name from employee
    where dep_id in 
    (select id from department where name='技术');
    
    #查看不足1人的部门名
    select name from department
    where id in 
    (select dep_id from employee group by dep_id having count(id) <=1);

     

    带比较运算符的子查询

    #查询大于所有人平均年龄的员工名与年龄
    select name,age from employee where age > (select avg(age) from employee);
    
    #查询大于部门内平均年龄的员工名、年龄
    select t1.name,t1.age from emp t1
    inner join 
    (select dep_id,avg(age) avg_age from emp group by dep_id) 
    t2 on t1.dep_id = t2.dep_id
    where t1.age > t2.avg_age;

    带EXISTS关键字的子查询
    EXISTS关字键字表示存在。在使用EXISTS关键字时,内层查询语句不返回查询的记录。
    而是返回一个真假值。
    True或False当返回True时,外层查询语句将进行查询;当返回值为False时,外层查询语句不进行查询

    select * from employee
    where exists
    (select id from department where id=203);#结果为True 若把id=205,结果为false
    

      

    视图

    是一个虚拟表,其内容由查询定义。同真实的表一样,视图包含一系列带有名称的列和行数据

    视图有如下特点; 
      1. 视图的列可以来自不同的表,是表的抽象和逻辑意义上建立的新关系。 
      2. 视图是由基本表(实表)产生的表(虚表)。 
      3. 视图的建立和删除不影响基本表。 
      4. 对视图内容的更新(添加、删除和修改)直接影响基本表。 
      5. 当视图来自多个基本表时,不允许添加和删除数据。  
    创建视图
    create view 视图名称 as sql 查询语句 
    使用视图
    select * from 视图名称;
    修改视图
    alter view 视图名称 AS SQL语句
    删除视图
    drop view 视图名称;
    create view emp_view as select * from employee;
    select * from emp_view;
    update emp_view set name='blueky' where id=5; 
    select * from employee;#epmloyee表中的字段也变成blueky	
    alter view emp_view as select * from employee where age>28;
    drop view emp_view;

     

    触发器:监视某种情况,并触发某种操作。

    触发器创建语法四要素:1.监视地点(table)
               2.监视事件(insert/update/delete)
                3.触发时间(after/before)
               4.触发事件(insert/update/delete)

    创建触发器语法

    create trigger triggerName after/before insert/update/delete
    on 表名 for each row #这句话是固定的
    begin
    #需要执行的sql语句
    end
    #注意1:after/before: 只能选一个 ,after 表示 后置触发, before 表示前置触发
    #注意2:insert/update/delete:只能选一个 
    #准备表
    CREATE TABLE cmd (
    id INT PRIMARY KEY auto_increment,
    USER CHAR (32),
    priv CHAR (10),
    cmd CHAR (64),
    sub_time datetime, #提交时间
    success enum ('yes', 'no') #0代表执行失败
    );
    
    CREATE TABLE errlog (
    id INT PRIMARY KEY auto_increment,
    err_cmd CHAR (64),
    err_time datetime
    );
    
    #创建触发器
    delimiter //
    CREATE TRIGGER tri_after_insert_cmd AFTER INSERT ON cmd FOR EACH ROW
    BEGIN
    IF NEW.success = 'no' THEN #等值判断只有一个等号
    INSERT INTO errlog(err_cmd, err_time) VALUES(NEW.cmd, NEW.sub_time) ; #必须加分号
    END IF ; #必须加分号
    END//
    delimiter ;
    
    #往表cmd中插入记录,触发触发器,根据IF的条件决定是否插入错误日志
    INSERT INTO cmd (
    USER,
    priv,
    cmd,
    sub_time,
    success
    )
    VALUES
    ('egon','0755','ls -l /etc',NOW(),'yes'),
    ('egon','0755','cat /etc/passwd',NOW(),'no'),
    ('egon','0755','useradd xxx',NOW(),'no'),
    ('egon','0755','ps aux',NOW(),'yes');
    
    #删除触发器
    drop trigger tri_after_insert_cmd;

    事务
    事务用于将某些操作的多个SQL作为原子性操作,一旦有某一个出现错误,即可回滚到原来的状态,从而保证数据库数据完整性。

    事物的特性:原子性、一致性、隔离性、持久性。
    在 MySQL 中只有使用了 Innodb 数据库引擎的数据库或表才支持事务。
    事务处理可以用来维护数据库的完整性,保证成批的 SQL 语句要么全部执行,要么全部不执行。
    事务用来管理 insert,update,delete 语句
    SET AUTOCOMMIT=0 ;禁止自动提交 和 SET AUTOCOMMIT=1 开启自动提交.

    数据锁
    当并发事务同时访问一个资源时,有可能导致数据不一致,就需要一种机制来将数据访问顺序化,以保证数据库数据的一致性

    多个事务同时读取一个对象的时候,是不会有冲突的。同时读和写,或者同时写才会产生冲突。

    因此为了提高数据库的并发性能,通常会定义两种锁:共享锁和排它锁。

    共享锁:共享锁(S)表示对数据进行读操作。因此多个事务可以同时为一个对象加共享锁。
    排他锁:排他锁(X)表示对数据进行写操作。如果一个事务对 对象加了排他锁,其他事务就不能再给它加任何锁了。
    

     

     1 1. 查看岗位是teacher的员工姓名、年龄
     2 select name,age from employee where post='teacher';
     3 
     4 2. 查看岗位是teacher且年龄大于30岁的员工姓名、年龄
     5 select name,age from employee where post='teacher' and age>30;
     6 
     7 3. 查看岗位是teacher且薪资在9000-1000范围内的员工姓名、年龄、薪资
     8 select name,age,salary from employee where salary between 9000 and 10000;
     9 
    10 4. 查看岗位描述不为NULL的员工信息
    11 select * from employee where post_comment is not null;
    12 
    13 5. 查看岗位是teacher且薪资是10000或9000或30000的员工姓名、年龄、薪资
    14 select name,age,salary from employee where post='teacher' and salary in(10000,9000,30000); 
    15 
    16 6. 查看岗位是teacher且薪资不是10000或9000或30000的员工姓名、年龄、薪资
    17 select name,age,salary from employee where post='teacher' and salary not in(10000,9000,30000); 
    18 
    19 
    20 7. 查看岗位是teacher且名字是jin开头的员工姓名、年薪
    21 #select name,salary from employee where post='teacher' and name like 'jin_';
    22 select name,salary from employee where post='teacher' and name like 'jin%';
    23 
    24 
    25 
    26 
    27 1. 查询岗位名以及岗位包含的所有员工名字
    28 select post,group_concat(name) from employee group by post;
    29 
    30 2. 查询岗位名以及各岗位内包含的员工个数
    31 select post,count(id) from employee group by post;
    32 
    33 3. 查询公司内男员工和女员工的个数
    34 select sex,count(id) from employee group by sex; 
    35 4. 查询岗位名以及各岗位的平均薪资
    36 select post,avg(salary) from employee group by post;
    37 
    38 5. 查询岗位名以及各岗位的最高薪资
    39 select post,max(salary) from employee group by post;
    40 
    41 6. 查询岗位名以及各岗位的最低薪资
    42 select post,min(salary) from employee group by post;
    43 
    44 
    45 7. 查询男员工与男员工的平均薪资,女员工与女员工的平均薪资
    46 select sex,avg(salary) from employee group by sex;
    47 
    48 
    49 1. 查询各岗位内包含的员工个数小于2的岗位名、岗位内包含员工名字、个数
    50 select post,group_concat(name),count(id) from employee group by post having count(id)<2;
    51 2. 查询各岗位平均薪资大于10000的岗位名、平均工资
    52 select post,avg(salary) from employee group by post having avg(salary)>10000;
    53 3. 查询各岗位平均薪资大于10000且小于20000的岗位名、平均工资
    54 select post,avg(salary) from employee group by post having avg(salary)>10000 and avg(salary)<20000;
    55 
    56 
    57 
    58 1. 查询所有员工信息,先按照age升序排序,如果age相同则按照hire_date降序排序
    59 select * from employee order by age asc,hire_date desc;
    60 
    61 2. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资升序排列
    62 select post,avg(salary) from employee where avg(salary)>10000 group by post order by avg(salary) asc;#错误
    63 select post,avg(salary) from employee group by post having avg(salary)>10000 order by avg(salary) asc;
    64 
    65 3. 查询各岗位平均薪资大于10000的岗位名、平均工资,结果按平均薪资降序排列
    66 select post,avg(salary) from employee group by post having avg(salary)>10000 order by avg(salary) desc;
    67 
    68 
    69 1. 分页显示,每页5条
    70 select * from  employee limit 0,5;
    71 select * from  employee limit 5,5;
    72 select * from  employee limit 10,5;
    73 
    74 1.以内连接的方式查询employee和department表,并且employee表中的age字段值必须大于25,
    75 即找出年龄大于25岁的员工以及员工所在的部门
    76 select employee.name,department.name from employee 
    77     inner join department on employee dep_id=department.id where age>25;
    78     
    79 2.以内连接的方式查询employee和department表,并且以age字段的升序方式显示
    80 select employee.id,employee.name,employee.age,department.name from employee,department
    81     where employee dep_id=department.id  
    82     and age>25
    83     order by age asc;
    84     
    85 1.查询平均年龄在25岁以上的部门名
    86 select * from department 
    87     where id in 
    88         (select dep_id from employee group by dep_id having avg(age)>25);
    89     
    90 2.查看技术部员工姓名
    91 select name from employee
    92         where dep_id in
    93             (select id from department where name='技术');
    94             
    95 3.查看不足1人的部门名
    96 select name from department
    97     where id in 
    98         (select dep_id from employee group by dep_id having count(id)<=1);
    mysql练习题

     

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  • 原文地址:https://www.cnblogs.com/xfxing/p/9330748.html
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