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  • 第十一章运算符重载 简单

    //1 运算符重载
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1;}
    	~num(){}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<n.get()<<endl;
    	//n++; 
        return 0;
    }
    
    /*
    //2 在成员函数中实现自加
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1;}
    	~num(){}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<n.get()<<endl;
    	//n++; 
    	n.add();
    	cout<<n.get()<<endl;
        return 0;
    }
    */
    
    /*
    // 3 重载前置自加运算符
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1;}
    	~num(){}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	void operator++(){ ++n;}
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<n.get()<<endl;
    	//n++; 
    	//n.add();
    	++n;
    	cout<<n.get()<<endl;
        return 0;
    }
    
    */
    
    // 4 重载前置自加运算符
    /*
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1;}
    	~num(){}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	void operator++(){ ++n;}
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<n.get()<<endl;
    	//n++; 
    	//n.add();
    	//++n;
    
    	//num i = ++n;
    
    
    	cout<<n.get()<<endl;
        return 0;
    }
    */
    
    
    /*
    //5 创建临时对像
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1;}
    	~num(){}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	num operator++()
    	{ 
    		++n;
    		num t;
    		t.set(n);
    		return t;
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<"n:"<<n.get()<<endl;
    	//n++; 
    	n.add();
    	num i = ++n;
    	cout<<"i:"<<i.get()<<endl;
        return 0;
    }
    
    */
    
    
    // 6 创建无名临时对像
    /*#include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	num operator++()
    	{ 
    		++n;
    		return num(n); //这里返回一个创建的无名临时对像,他执行的是一个带参数的构造函数
    		//num t;
    		//t.set(n);
    		//return t;
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<"n:"<<n.get()<<endl;
    	//n++; 
    	n.add();
    	num i = ++n;
    	cout<<"i:"<<i.get()<<endl;
        return 0;
    }*/
    /*
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	num(const num&s){ this->n = s.n; cout<<"这里执行了带参数的复制构造函数"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	num operator++()
    	{ 
    		++n;
    		return *this; //这里其实是进行了复制构造函数
    		//return num(n);
    		//num t;
    		//t.set(n);
    		//return t;
    	}
    
    
    	//重载后执自加运算符
    	const num operator++(int o)
    	{
    		
    	     num temp(*this); //临时对像, *this表示operator++进行自加的当前对像
    		 //++n; //这里的n是指原实对像的n,也就是this对像的n
    		 this->n++; //与上等同 ++n;
    		 return temp; //然后我们把临时对像返回去
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num i;
    	cout<<"i:"<<i.get()<<endl;
    	i.add();
    	cout<<"i:"<<i.get()<<endl;
    	num n = i++;
    	cout<<"i:"<<i.get()<<endl;
    	cout<<"n:"<<n.get()<<endl;
    	
    	//num n = i++;
    
        return 0;
    }*/
    
    
    // 7 取消创建临时对象
    /*#include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	num(const num&s){ this->n = s.n; cout<<"这里执行了带参数的复制构造函数"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	num operator++()
    	{ 
    		++n;
    		return *this; //这里其实是进行了复制构造函数
    		//return num(n);
    		//num t;
    		//t.set(n);
    		//return t;
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num n;
    	n.set(11);
    	cout<<"n:"<<n.get()<<endl;
    	//n++; 
    	n.add();
    	num i = ++n; //这里进行重载运算符
    	cout<<"i:"<<i.get()<<endl;
        return 0;
    }*/
    
    
    //9 重载后置自加运算
    //如果x=1
    // y = ++x;  执行完以后,x y 都等于2
    // 前执自加是先将++x执行,然后赋值给y
    // y = x++;  
    // 而后执自加是先将x赋值给y, 然后进行x++
    // 那么这里的x = 2;  y = 1;
    /*#include <iostream>
    using namespace std;
    int main()
    {
       int i= 1;
       int y, x;
       y = ++i;
       cout<<"i:"<<i<<", y:"<<y<<endl;
       i = 1;
       x = i ++;
       cout<<"i:"<<i<<", x:"<<x<<endl;
       return 0;
    }*/
    
    
    //后执自加
    /*#include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	num(const num&s){ this->n = s.n; cout<<"这里执行了带参数的复制构造函数"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    	num operator++()
    	{ 
    		++n;
    		return *this; //这里其实是进行了复制构造函数
    		//return num(n);
    		//num t;
    		//t.set(n);
    		//return t;
    	}
    
    
    	//重载后执自加运算符
    	const num operator++(int o)
    	{
    		
    	     num temp(*this); //临时对像, *this表示operator++进行自加的当前对像
    		 //++n; //这里的n是指原实对像的n,也就是this对像的n
    		 this->n++; //与上等同 ++n;
    		 return temp; //然后我们把临时对像返回去
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num i;
    	cout<<"i:"<<i.get()<<endl;
    	i.add();
    	cout<<"i:"<<i.get()<<endl;
    	num n = i++;
    	cout<<"i:"<<i.get()<<endl;
    	cout<<"n:"<<n.get()<<endl;
    	
    	//num n = i++;
    
        return 0;
    }*/
    
    
    //10 重载加法运算符函数
    /*既然使用关键字operator配合运算符++可以实现对像的自加,那么关键字operator配合运算符+就可以实现将对像相加,本节我们就来学习
    一下重载加法运算符operator+,减法运算符的道理与加法相同,这里就不多说了
    在使用operator+之前我们先来看如查没有加运算符,比如说我们定义了两个对像sum a, b;
    然后将这两个对像相加的结果赋给第三个对像
    sum c = a+b;
    我们要实现这样的操作仍然要定义一个add()函数,该函数被对像a所调用,然后在函数中将对像b作为参数传递到add()函数中去
    然后在函数中将两上对像的成员变量相加,并将结果传递到构造函数中,最后返回这个构造函数,该函数的胚体写法与调用如下
    */
    
    /*
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	num(const num&s){ this->n = s.n; cout<<"这里执行了带参数的复制构造函数"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    
    	num add(const num&x){ return num(this->n + x.n); }
    	num operator++()
    	{ 
    		++n;
    		return *this; //这里其实是进行了复制构造函数
    		//return num(n);
    		//num t;
    		//t.set(n);
    		//return t;
    	}
    
    
    	//重载后执自加运算符
    	const num operator++(int o)
    	{
    		
    	     num temp(*this); //临时对像, *this表示operator++进行自加的当前对像
    		 //++n; //这里的n是指原实对像的n,也就是this对像的n
    		 this->n++; //与上等同 ++n;
    		 return temp; //然后我们把临时对像返回去
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num one(1), two(2), three;
    	three = one.add(two);
    	cout<<"one:"<<one.get()<<endl;
    	cout<<"two:"<<two.get()<<endl;
    	cout<<"three:"<<three.get()<<endl;
    
    
    
    
        return 0;
    }*/
    
    // 重载加法运算符函数
    /*
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	num(const num&s){ this->n = s.n; cout<<"这里执行了带参数的复制构造函数"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    
    	num add(const num&x){ return num(this->n + x.n); }
    	
    	//重载+运算符,对两个对像进行相加操作
    	const num operator+(const num &x){ return (this->n + x.n); }
    
    	const num operator-(const num &x){ return (this->n - x.n); }
    
    	num operator++()
    	{ 
    		++n;
    		return *this; //这里其实是进行了复制构造函数
    	}
    
    
    	//重载后执自加运算符
    	const num operator++(int o)
    	{
    	     num temp(*this); //临时对像, *this表示operator++进行自加的当前对像
    		 //++n; //这里的n是指原实对像的n,也就是this对像的n
    		 this->n++; //与上等同 ++n;
    		 return temp; //然后我们把临时对像返回去
    	}
    private:
    	int n;
    
    };
    int main()
    {
    	num one(1), two(2), three;
    	//three = one + two;
        //three = one.add(two);
    
    	three = one - two;
    	cout<<"one:"<<one.get()<<endl;
    	cout<<"two:"<<two.get()<<endl;
    	cout<<"three:"<<three.get()<<endl;
        return 0;
    }*/
    
    
    // 12 重载赋值运算函数operator=\
    
    /*
    #include <iostream>
    using namespace std;
    class num
    {
    public:
    	num(){ n=1; cout<<"构造函数执行"<<endl;}
    	num(int i){ n = i; cout<<"带参数的构造函数"<<endl;}
    	~num(){ cout<<"析构函数执行"<<endl;}
    	num(const num&s){ this->n = s.n; cout<<"这里执行了带参数的复制构造函数"<<endl;}
    	int get()const{ return n;}
    	void set(int x){ n = x;}
    	void add(){ ++n; }
    
    	num add(const num&x){ return num(this->n + x.n); }
    	
    	//重载+运算符,对两个对像进行相加操作
    	const num operator+(const num &x){ return (this->n + x.n); }
    
    	const num operator-(const num &x){ return (this->n - x.n); }
    
    	const num equal(const num&x){ this->n = x.get(); return *this; }
    
    
    	const num operator=(const num&x){
    		if(this == &x){
    		    return *this;
    		} 
    		cout<<"operator=函数在调用"<<endl;
            this->n = x.get();
    		return *this;
    	}
    
    
    	num operator++()
    	{ 
    		++n;
    		return *this; //这里其实是进行了复制构造函数
    	}
    
    
    	//重载后执自加运算符
    	const num operator++(int o)
    	{
    	     num temp(*this); //临时对像, *this表示operator++进行自加的当前对像
    		 //++n; //这里的n是指原实对像的n,也就是this对像的n
    		 this->n++; //与上等同 ++n;
    		 return temp; //然后我们把临时对像返回去
    	}
    
    
    
    	//赋值=运算符重载
    	
    private:
    	int n;
    
    };
    int main()
    {
    	num one(1), two(2), three;
    	//three = one + two;
        //three = one.add(two);
    
    	//three = one - two;
    	//one.equal(two);
    	//one = two;
    
    	cout<<"one:"<<one.get()<<endl;
    	cout<<"two:"<<two.get()<<endl;
    	cout<<"three:"<<three.get()<<endl;
        return 0;
    }*/
    
    // 18 转换类型运算符
    /*#include <iostream>
    using namespace std;
    class A
    {
    public:
    	A(int x){ i = x; cout<<"构造函数执行"<<i<<endl;}
    	//如果调用带两个参数的构造函数将产生错误
    	//A(int x, int y){ i = x; cout<<"构造函数执行"<<i<<endl;}
    	~A(){cout<<"析构造函数执行"<<i<<endl;}
    	void get(){ cout<<i<<endl;}
    private:
    	int i;
    };
    int main()
    {
    	A a(33);
    	a.get();
    	a = 1000; //在将1000赋值给a时,执行带一个参数的构造函数,会生成一个临时的对像,然后调用析构函数
    	a.get();
    
    	a = A(2); //强制类型表达式, 将2转换成A 的值
    
    
    
        return 0;
    }*/
    
    
    /*
    #include <iostream>
    using namespace std;
    class A
    {
    public:
    	A(int x){ i = x; cout<<"构造函数执行"<<i<<endl;}
    	//如果调用带两个参数的构造函数将产生错误
    	//A(int x, int y){ i = x; cout<<"构造函数执行"<<i<<endl;}
    	~A(){cout<<"析构造函数执行"<<i<<endl;}
    	void get(){ cout<<i<<endl;}
    	operator int(){ return i;}
    private:
    	int i;
    };
    int main()
    {
    
    	A a(33);
    	a.get();
    	int x = 999;
    	x = a;
    	a.get();
    	cout<<x<<endl;
    
    
    
    
        return 0;
    }*/
    
    #include <iostream>
    using namespace std;
    class A 
    {
    public:
    	A(int x){i=x;cout<<"构造函数执行!"<<i<<endl;}
    	~A(){cout<<"析构函数执行!"<<i<<endl;}
    	void get(){cout<<i<<endl;}
    
    	
    	operator int()
    	{
    	    cout<<"operator int"<<i<<endl;
    		return i;
    	}
    private:
    	int i;
    };
    
    struct   B
    { 
    int   a; 
    B(int   i):a(i){}	
    //重载运算符int,可以将类进行类型换转为int型
    operator   int()   const   {   return   a;   } 
    }; 
    
    
    int main()
    {
    	A a(33);
    	a.get();
    	int x=999;
    	x=a;
    
    
    	B   aa(22); 
    	int i = int(aa);
    	int j = aa;
    	cout<<"i:"<<i<<endl;
    	cout<<"j:"<<aa<<endl; //作用一样;
    
    
    	//a.get();
    	//cout<<endl;
    	//cout<<x<<endl;
    	return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/xiangxiaodong/p/2572408.html
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