Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
不使用额外空间:这里没有实例化一个对象,只是引用对象,所以不会开辟新内存空间
用一个快指针和一个慢指针,当两个指针相遇,说明有环
/** * Definition for singly-linked list. * class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public boolean hasCycle(ListNode head) { if(head==null||head.next==null||head.next.next==null) return false; ListNode fast=head.next.next; ListNode slow=head.next; while(fast!=null&&fast.next!=null){ if(fast==slow) return true; fast=fast.next.next; slow=slow.next; } return false; } }