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  • Oracle数据库----查询

    --笛卡尔集
    select empno,ename, 员工表.deptno, 部门表.deptno, dname
    from 部门表, 员工表;

    --添加合适的条件,可以避免笛卡尔集,从而得到正确的多表查询记录
    select empno,ename, 员工表.deptno, 部门表.deptno, dname
    from 部门表, 员工表
    where 部门表.deptno = 员工表.deptno;

    --查询员工信息,要求显示:员工号,姓名,职位,部门名称

    --等值连接
    select empno,ename,job,dname from emp, dept where emp.deptno = dept.deptno;

    --多个条件的等值连接,使用AND操作符
    select e.empno,e.ename,e.job,d.dname,d.deptno from emp e, dept d where e.deptno = d.deptno and e.deptno=10;


    --显示所有员工的员工号、姓名、工资及其工资的等级。

    select * from salgrade;

    --非等值连接
    select e.empno, e.ename, e.sal, s.grade from emp e, salgrade s where e.sal between losal and hisal;

    --按部门统计员工的人数,要求显示:部门号,部门名称,人数

    select d.deptno,d.dname,count(e.empno) from dept d, emp e where d.deptno = e.deptno group by d.deptno, d.dname;

    select * from dept;

    select * from emp where deptno=40;

    --外连接
    select d.deptno,d.dname,count(e.empno) from dept d, emp e where d.deptno = e.deptno(+) group by d.deptno, d.dname;

    --自连接

    --查询所有员工的姓名和直属上级的姓名
    select e.ename,m.ename
    from emp e, emp m
    where e.mgr = m.empno;

    --验证 ford-->jones
    select * from emp;

    --cross join
    select d.dname, e.ename, d.deptno, e.deptno from dept d cross join emp e;
    select count(*) from emp;
    select count(*) from dept;


    --natural join
    --查询员工名、工资以及所在部门名称
    select e.ename, e.sal, d.dname from dept d natural join emp e;

    --内连接
    --using子句
    select e.ename,e.sal, d.dname from dept d join emp e using(deptno);

    --通过on指定内连接的条件
    select e.ename,e.sal, d.dname from dept d join emp e on d.deptno = e.deptno;

    --内连接的关键字inner join, inner通常省略
    select e.ename,e.sal, d.dname from dept d inner join emp e on d.deptno = e.deptno;

    --左外连接
    select e.ename,e.sal, d.dname from dept d left join emp e on d.deptno = e.deptno;

    --右连接
    select e.ename,e.sal, d.dname from dept d right join emp e on d.deptno = e.deptno;

    --完全连接
    select e.ename,e.sal, d.dname from dept d full join emp e on d.deptno = e.deptno;

    --emp01
    create table emp01
    as
    select * from emp where deptno in(10,20);

    --emp02
    create table emp02
    as
    select * from emp where deptno in(20,30);

    --合并显示emp01表和emp02表所有雇员的部门编号、员工号、员工姓名。
    --10号部门有3个、20号部门有5个、
    select * from emp01;
    --30号部门有6个、
    select * from emp02;

    --union 14个记录
    select deptno, empno, ename from emp01
    union
    select deptno, empno, ename from emp02;

    --union all
    --通过部门号进行排序
    select deptno, empno, ename from emp01
    union all
    select deptno, empno, ename from emp02
    order by deptno;

    --通过列值进行排序,1代表第一列
    select deptno, empno, ename from emp01
    union all
    select deptno, empno, ename from emp02
    order by 1;

    --intersect
    select deptno, empno, ename from emp01
    intersect
    select deptno, empno, ename from emp02;

    --minus
    select deptno, empno, ename from emp01
    minus
    select deptno, empno, ename from emp02;

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  • 原文地址:https://www.cnblogs.com/xiaomifeng1010/p/11111914.html
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