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  • Lc262-行程和用户

    select
        t.request_at Day, 
        (
            round(count(if(status != 'completed', status, null)) / count(status), 2)
        ) as 'Cancellation Rate'
    from
        Users u inner join Trips t
    --这块仅仅关联客户id,我认为应该关联司机id
    on
        u.Users_id = t.Client_Id 
    and
    --我认为应该把角色也携带上
        u.banned != 'Yes'
    where
        t.Request_at >= '2013-10-01'
    and
        t.Request_at <= '2013-10-03'
    group by
        t.Request_at
    Trips 表中存所有出租车的行程信息。每段行程有唯一键 Id,Client_Id 和 Driver_Id 是 Users 表中 Users_Id 的外键。Status 是枚举类型,枚举成员为 (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’)。
    
    +----+-----------+-----------+---------+--------------------+----------+
    | Id | Client_Id | Driver_Id | City_Id |        Status      |Request_at|
    +----+-----------+-----------+---------+--------------------+----------+
    | 1  |     1     |    10     |    1    |     completed      |2013-10-01|
    | 2  |     2     |    11     |    1    | cancelled_by_driver|2013-10-01|
    | 3  |     3     |    12     |    6    |     completed      |2013-10-01|
    | 4  |     4     |    13     |    6    | cancelled_by_client|2013-10-01|
    | 5  |     1     |    10     |    1    |     completed      |2013-10-02|
    | 6  |     2     |    11     |    6    |     completed      |2013-10-02|
    | 7  |     3     |    12     |    6    |     completed      |2013-10-02|
    | 8  |     2     |    12     |    12   |     completed      |2013-10-03|
    | 9  |     3     |    10     |    12   |     completed      |2013-10-03| 
    | 10 |     4     |    13     |    12   | cancelled_by_driver|2013-10-03|
    +----+-----------+-----------+---------+--------------------+----------+
    Users 表存所有用户。每个用户有唯一键 Users_Id。Banned 表示这个用户是否被禁止,Role 则是一个表示(‘client’, ‘driver’, ‘partner’)的枚举类型。
    
    +----------+--------+--------+
    | Users_Id | Banned |  Role  |
    +----------+--------+--------+
    |    1     |   No   | client |
    |    2     |   Yes  | client |
    |    3     |   No   | client |
    |    4     |   No   | client |
    |    10    |   No   | driver |
    |    11    |   No   | driver |
    |    12    |   No   | driver |
    |    13    |   No   | driver |
    +----------+--------+--------+
    写一段 SQL 语句查出 2013年10月1日 至 2013年10月3日 期间非禁止用户的取消率。基于上表,你的 SQL 语句应返回如下结果,取消率(Cancellation Rate)保留两位小数。
    
    取消率的计算方式如下:(被司机或乘客取消的非禁止用户生成的订单数量) / (非禁止用户生成的订单总数)
    
    +------------+-------------------+
    |     Day    | Cancellation Rate |
    +------------+-------------------+
    | 2013-10-01 |       0.33        |
    | 2013-10-02 |       0.00        |
    | 2013-10-03 |       0.50        |
    +------------+-------------------+
    
    来源:力扣(LeetCode)
    链接:https://leetcode-cn.com/problems/trips-and-users
    著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
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  • 原文地址:https://www.cnblogs.com/xiaoshahai/p/12190391.html
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