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  • 401 Binary Watch 二进制手表

    详见:https://leetcode.com/problems/binary-watch/description/

    C++:

    class Solution {
    public:
        vector<string> readBinaryWatch(int num) 
        {
            vector<string> res;
            vector<int> hour{8, 4, 2, 1}, minute{32, 16, 8, 4, 2, 1};
            for (int i = 0; i <= num; ++i) 
            {
                vector<int> hours = generate(hour, i);
                vector<int> minutes = generate(minute, num - i);
                for (int h : hours)
                {
                    if (h > 11)
                    {
                        continue;
                    }
                    for (int m : minutes)
                    {
                        if (m > 59)
                        {
                            continue;
                        }
                        res.push_back(to_string(h) + (m < 10 ? ":0" : ":") + to_string(m));
                    }
                }
            }
            return res;
        }
        vector<int> generate(vector<int>& nums, int cnt) 
        {
            vector<int> res;
            helper(nums, cnt, 0, 0, res);
            return res;
        }
        void helper(vector<int>& nums, int cnt, int pos, int out, vector<int>& res) 
        {
            if (cnt == 0) 
            {
                res.push_back(out);
                return;
            }
            for (int i = pos; i < nums.size(); ++i) 
            {
                helper(nums, cnt - 1, i + 1, out + nums[i], res);
            }
        }
    };
    

     参考:https://www.cnblogs.com/grandyang/p/5896454.html

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  • 原文地址:https://www.cnblogs.com/xidian2014/p/8854892.html
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